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Musya8 [376]
2 years ago
8

When blocking in football, why does a defending lineman often attempt to get his body under that of his opponent and push forwar

d?
Physics
2 answers:
timurjin [86]2 years ago
4 0

Answer:

because he is trying to break past you and sack your quarterback

Explanation:

ryzh [129]2 years ago
3 0
With the lineman's weight underneath the defender's, traction is increased with the lineman's feet and the ground. Friction is increased because the total force of both linemen give a larger opposing force of friction, making it harder for the defender to get around him.


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Because the time was the same for each segment you know the speed was the same for each segment
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Answer:

Market segmentation helps you send the right message, every time, by efficiently targeting specific groups of consumers.

Explanation:

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2 years ago
A woman does 260 J of work to move a table 1.9 m across the floor. What is the magnitude of the force applied by the woman to th
balandron [24]

Answer:136.8N

Explanation:

Work=260joules

Distance=1.9m force=?

Force=work/distance

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3 years ago
Find the velocity. 10 points. Will give brainliest!
BARSIC [14]

Answer:

6.060606...

Explanation:

To figure out velocity, you divide the distance by the time it takes to travel that same distance, then you add your direction to it. So the distance would be 1000m and the time would be 2 minutes and 45 seconds and if you convert the minutes into fractions you would get 165 seconds than you would divide 1000m by 165 seconds and you would get 6.060606... seconds as her average velocity

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3 years ago
Post WWII Germany was divided into four zones with the Americans occupying one zone and all of the following countries occupying
maxonik [38]

Answer:

b. Italy

Explanation:

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2 years ago
12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it
vodomira [7]

Answer:

We kindly invite you to read carefully the explanation and check the image attached below.

Explanation:

According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:

v_{f} = v_{o}+a\cdot (t-t_{o}) (1)

Where:

v_{o} - Initial velocity, measured in meters per second.

v_{f} - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t_{o} - Initial time, measured in seconds.

t - Final time, measured in seconds.

Now we obtain the kinematic equations for thrust and free fall stages:

Thrust (v_{o} = 0\,\frac{m}{s}, a = 30\,\frac{m}{s^{2}}, t_{o} = 0\,s, 0\,s\le t< 30\,s)

v = 30\cdot t (2)

Free fall (v_{o} = 900\,\frac{m}{s}, a = -9.807\,\frac{m}{s}, t_{o} = 30\,s, 30\,s \le t \le 120\,s)

v = 900-9.81\cdot (t-30) (3)

Now we created the graph speed-time, which can be seen below.

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2 years ago
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