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3 years ago

Referring to the scale is a way to estimate the wind speed.

Chemistry

2 answers:

Sonja [21]3 years ago

8 0

Answer:

The Beaufort scale measures wind speed.

Explanation:

One way to measure wind speed is by observing its effects on objects. In 1805, a British naval officer named Sir Francis Beaufort developed a wind speed scale that refers to the movement of objects. The Beaufort Scale is a good way to introduce your students to the concept of wind speed.

WINSTONCH [101]3 years ago

8 0

The Beaufort scale measures wind speed

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Is this right, i dont know how to do this?

aliina [53]

Your answer, I believe, is correct. I'm no expert at chemistry tho.

Tyler Dewitt has some great YouTube vids on chem that have saved my butt on multiple occasions. you should check them out. very helpful

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3 years ago

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If you have a fever, and your temperature is 39C what is your temperature in Fahrenheit.

Vadim26 [7]

The formula to convert from Celsius to Fahrenheit is F = 9/5C + 32 or F = (C*1,8)+32

F = 9/5*39 + 32 = 70,2 + 32 = 102,2° F

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3 years ago

The chemical properties of an element are largely determined by its

Savatey [412]

The chemical properties of an element are largely determined by its number of valence electrons. The answer is letter D. The rest of the choices do not answer the question above.

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3 years ago

Which sample of argon contains a total of 3.01 x 10^23 molecules at STP?

soldi70 [24.7K]

Answer:option d

Explanation:

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3 years ago

A mixture of 14.0 grams of H2, 84.0 grams of N2, and 64.0 grams of O2 are placed in a flask. The partial pressure of the O2 is 7

Hitman42 [59]

Answer:

$P_{tot}=465.27torr$

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to use the Dalton's law, in order to solve this problem. However, we first need to calculate the mole fraction of oxygen by firstly calculating the moles of each gas:

$n_{H_2}=\frac{14.0g}{2.02g/mol} =6.93mol\\\\n_{N_2}=\frac{84.0g}{28.02g/mol}=3.00mol\\\\n_{O_2}=\frac{64.0}{16.00g/mol} =2.00mol$

Next, we calculate such mole fraction as follows:

$x_{O_2}=\frac{2}{6.93+3+2} =0.168$

Then, given the following equation:

$P_{O_2}=P_{tot}*x_{O_2}$

So we solve for the total pressure as follows:

$P_{tot}=\frac{P_{O_2}}{x_{O_2}} \\\\P_{tot}=\frac{78.00torr}{0.168} \\\\P_{tot}=465.27torr$

Regards!

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3 years ago