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Assoli18 [71]
3 years ago
9

How many carbon atoms are there in a diamond (pure carbon) with a mass of "48" mg?

Chemistry
1 answer:
blagie [28]3 years ago
7 0

Answer:

              3.47 × 10²³ C atoms

Solution:

Data Given:

                 Mass of Diamond  =  48 mg  =  0.048 g

                 M.Mass of Diamond  =  12.01 g.mol⁻¹ (as it is purely Carbon)

Step 1: Calculate Moles of Diamond as,

                 Moles  =  Mass ÷ M.Mass

Putting values,

                 Moles  =  0.048 g ÷ 12.01 g.mol⁻¹

                 Moles  =  0.576 mol

Step 2: Calculate number of Carbon atoms,

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Carbon atoms can be written as,

                 Moles  =  Number of C Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Solving for Number of C atoms,

                 Number of C atoms  =  Moles × 6.022 × 10²³ Atoms.mol⁻¹

Putting value of moles,

                 Number of C atoms  =  0.576 mol × 6.022 × 10²³ Atoms.mol⁻¹

                 Number of C atoms =  3.47 × 10²³ C atoms

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Josefina and Raul were comparing how sound moves through various mediums and how charge moves through conducting wires. They per
Fed [463]

They found that difference occurs in the speed of both sound and charges occur due to the difference in the type of medium.

Sound and charges needs specific medium for faster movement i.e. sound moves faster in solid as compared to liquid and gas whereas charges moves faster and easily in gold due to lower resistance which is followed by copper. Sound can move from solid, liquid and gases whereas charges move only in solid metal in which free electrons are present. The speed of sound and flow of current are affected due to difference in the arrangement of atoms in solid, liquid and gas.

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8 0
3 years ago
Entropy of a system decreases with decrease in Temperature T/F
Svet_ta [14]

Answer: The given statement is true.

Explanation:

Entropy means the measure of randomness present in a substance. That is, an increase in temperature will lead cause more motion in the particles of a substance more will be their kinetic energy.

As a result, there will occur more collisions due to which randomness of molecules will increase. Hence, there will be increase in entropy.

So, when we decrease the temperature then there will be decrease in motion of particles. As a result, lesser number of collisions will take place between them. Hence, degree of randomness will also decrease.

Thus, we can conclude the statement entropy of a system decreases with decrease in temperature, is true.

3 0
3 years ago
. Write the balanced equation, then outline the steps necessary to determine the information requested in each of the following:
mafiozo [28]

Answer:

See explanation

Explanation:

a) The equation of the reaction is;

2Na + Cl2 ------>2NaCl

Number of moles of sodium = 10g/23 g/mol = 0.43 moles

If 2 moles of sodium reacts with 1 mole of Cl2

0.43 moles reacts with 0.43 * 1/2 = 0.215 moles of Cl2

Mass =  0.215 moles of Cl2 *71 g/mol = 15.265 g

b) Equation of the reaction;

HgO -> Hg + O2

1.252 moles of HgO 1.252/32 gmol = 0.039 moles

1 mole of HgO  yields 1 mole of oxygen hence

0.039 moles of HgO yields   0.039 moles of oxygen

Mass of oxygen = 0.039 moles * 32 g/mol = 1.248 g

c) Equation of the reaction;

2NaNO3 -----> 2NaNO2 + O2

Number of moles of 128 g of oxygen = 128g/32 g/mol = 4 moles

2 moles of NaNO3  yields 1 mole of oxygen

x moles of NaNO3   yields 4 moles of oxygen

x = 8 moles of NaNo3

Mass of NaNO3 = 8 * 85 g/mol = 680 g of NaNo3

6 0
3 years ago
1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

___________________________________

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

3 0
3 years ago
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