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3 years ago

How many carbon atoms are there in a diamond (pure carbon) with a mass of "48" mg?

Chemistry

1 answer:

blagie [28]3 years ago

7 0

Answer:

3.47 × 10²³ C atoms

Solution:

Data Given:

Mass of Diamond = 48 mg = 0.048 g

M.Mass of Diamond = 12.01 g.mol⁻¹ (as it is purely Carbon)

Step 1: Calculate Moles of Diamond as,

Moles = Mass ÷ M.Mass

Putting values,

Moles = 0.048 g ÷ 12.01 g.mol⁻¹

Moles = 0.576 mol

Step 2: Calculate number of Carbon atoms,

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Carbon atoms can be written as,

Moles = Number of C Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Solving for Number of C atoms,

Number of C atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹

Putting value of moles,

Number of C atoms = 0.576 mol × 6.022 × 10²³ Atoms.mol⁻¹

Number of C atoms = 3.47 × 10²³ C atoms

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Vitek1552 [10]

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$\frac{4molPF_3}{1molP_4}$

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3 years ago

a 40-lb container of peat moss measure 14x20x30 inches and has an average density of 0.13 g/cm^3. how many bags of peat moss are

telo118 [61]

Volume of the peat moss = $14\times 20\times 30 inches$

= $8400 in^{3}$

Convert the above volume into $cm^{3}$

$1 in^{3}= 16.4 cm^{3}$

Thus, volume in $cm^{3}$ is:

Volume of peat moss = $8400 in^{3}\times \frac{16.4 cm^{3}}{1 in^{3}}$

= $137760 cm^{3}$

Now,

Total volume by using area and depth of the peat moss = $area of peat moss \times depth of peat moss$

= $(13 ft \times 25 ft)\times 1.9 inches$

= $(325 ft^{2})\times 1.9 inches$

Convert above values in $cm$ to get the value of volume in $cm^{3}$ :

$1 ft= 30.48 cm$

$1 in= 2.54 cm$

Thus, volume in $cm^{3}$ is:

Total volume = $(325 ft^{2}\times\frac{(30.48 cm)^{2}}{(1 ft)^{2}})\times (1.9 in\times \frac{2.54 cm}{1 in})$

= $301934.88 cm^{2}\times 4.826 cm$

= $1457137.73088 cm^{3}$

Now, number of bags is calculated by the ratio of total volume of the peat moss to the volume of the peat moss.

$Number of bags =\frac{total volume of peat moss}{volume of peat moss}$

Substitute the values of volume in above formula:

$Number of bags = \frac{1457137.73088 cm^{3}}{137760 cm^{3}}$

= $10.57$

≅ $11$ bags

Thus, number of bags of peat moss are needed to cover an area measure $13 ft$ by $25 ft$ to a depth of $1.9 inches$ are $11$ bags.

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