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ladessa [460]
3 years ago
6

Most asteroids _____.

Physics
1 answer:
Naily [24]3 years ago
7 0

Answer:

C

Explanation:

The answer is C cause ...  look at the file I added! Plz mark as brainlest! PASS THE TEST OR ASSIGNMNETT!

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Suppose that video game discs are a normal good. If the income of video game players​ increases, you predict that in the market
DENIUS [597]

Answer:

Both equilibrium price and quantity will increase.

Explanation:

An increase in the income of video game players will surely lead to an upward shift in the supply and demand curve. This shift in the supply and demand curve would affect the equilibrium price and quantity positively leading to a correspondent increase in the equilibrium price and quantity.

8 0
3 years ago
The weight of the mass added to the hanger is equal to the extra force on the gas, but what area should we use to calculate the
kari74 [83]

Answer: according to the Avagadro's law, volume is directly propotional to no of moles: VXn

according to the Charles law, volume is directly propotional to  temperatue: VXT

according to the Boyle's law, volume is inversely propotional to P: VX1/P

when we combine them we get:

VXnT1/P

V=knT/P

k= R(universal gas constant)

V=RnT/P

PV=nRT  

8 0
3 years ago
Desceibe how the ringing sound of a telephone
luda_lava [24]
<span>buzzed, droned, jangled, reverberated.</span>
5 0
3 years ago
A 50.0 g toy car is released from rest on a frictionless track with a vertical loop of radius R (loop-the-loop). The initial hei
Mariana [72]

Answer:

the speed of the car at the top of the vertical loop  v_{top} = 2.0 \sqrt{gR \ \ }

the magnitude of the normal force acting on the car at the top of the vertical loop   F_{N} = 1.47 \ \ N

Explanation:

Using the law of conservation of energy ;

mgh = mg (2R) + \frac{1}{2}mv^2_{top}\\\\mg ( 4.00 \ R) = mg (2R) + \frac{1}{2}mv^2_{top}\\\\g(4.00 \ R) = g (2R) + \frac{1}{2}v^2 _{top}\\\\v_{top} = \sqrt{2g(4.00R - 2R)}\\\\v_{top} = \sqrt{2g(4.00-2)R

v_{top} = 2.0 \sqrt{gR \ \ }

The  magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:

F_{N} = \frac{mv^2_{top}}{R} \ - mg\\\\F_{N} = \frac{m(2.0 \sqrt{gR})^2}{R} \ - mg\\\\F_{N} = [(2.0^2-1]mg\\\\F_{N} = [(2.0)^2 -1) (50*10^{-3} \ kg)(9.8 \ m/s^2]\\\\

F_{N} = 1.47 \ \ N

4 0
4 years ago
Which of the following is an example of the transformation of gravitational potential energy into motion energy (kinetic energy
nikklg [1K]

Answer:

A drop of water falling from a faucet into a sink

5 0
3 years ago
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