\sqrt[n]{x} -1\leq 12" align="absmiddle" class="latex-formula">
1 answer:
Answer:
Step-by-step explanation:
![3\sqrt[n]{x} -1\leq 12\\3\sqrt[n]{x} \leq 12+1\\\sqrt[n]{x} \leq \frac{13}{3}](https://tex.z-dn.net/?f=3%5Csqrt%5Bn%5D%7Bx%7D%20-1%5Cleq%2012%5C%5C3%5Csqrt%5Bn%5D%7Bx%7D%20%5Cleq%2012%2B1%5C%5C%5Csqrt%5Bn%5D%7Bx%7D%20%5Cleq%20%5Cfrac%7B13%7D%7B3%7D)
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Answer:
-11
Step-by-step explanation:
that's my answer please follow me
Answer:
Step-by-step explanation:
Remove the parentheses and combine the like terms:
7 - -9 = 7+ 9 = 16
6i - -8i = 6i +8i = 14i
The answer is 16 + 14i
Statement 1 is true.
-Hope this helps, have a nice day! :)
(17-5)(x+6)-(3x-12)=0
12(x+6)-(3x-12)=0
12x-(3x-12)+72=0
12x-3x+12+72=0
9x+84=0
9x=-84
x=9+1/3
