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Vlad1618 [11]
3 years ago
13

Can anyone help me!!!

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

3920 N.

Explanation:

that's what the answer is..

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A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i
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1. -23.2 J

The gravitational potential energy of the ball is given by

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m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

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In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J

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Again, the gravitational potential energy of the ball is given by

U=mgh

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J

3. 0 J

As before, the gravitational potential energy of the ball is given by

U=mgh

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J

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