1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
enyata [817]
3 years ago
15

It is a large body of air that has the same properties as the Earth's surface over which it develops.what is it?

Chemistry
1 answer:
Debora [2.8K]3 years ago
4 0
The answer is AIR MASS.

You might be interested in
I need help on this may u help me?
sergij07 [2.7K]

Answer:

just go to googel and it will tell you

Explanation:

7 0
2 years ago
Convert 6.90 x 10-3 km to nm3
marshall27 [118]
I’m sorry I’m really not sure how to answer this but have to respond to have this app I hope you have a good day:)
5 0
3 years ago
Which behavior did dr. Hernandez display
natulia [17]
Was there suppose to be a picture included?
5 0
3 years ago
Seawater is typically 3.5% salt and has a density of 1.03 g/mL. How many grams of salt would be needed to prepare enough seawate
Bas_tet [7]

Answer:

Amount of salt needed is around 2.3*10³ g

Explanation:

The salt content in sea water = 3.5 %

This implies that there is 3.5 g salt in 100 g sea water

Density of seawater = 1.03 g/ml

Volume of seawater = volume of tank = 62.5 L = 62500 ml

Therefore, the amount of seawater required is:

=Density*Volume = 1.03g/ml*62500ml = 6.44*10^{4} g

The amount of salt needed for the calculated amount of seawater is:

=\frac{6.44*10^{4}g\ water*3.5g\ salt }{100g\ water} =2254 g =2.3*10^{3} g

8 0
3 years ago
An herbicide contains only C, H, Cl, and N. The complete combustion of a 200.0 mg sample of the herbicide in excess oxygen produ
MAVERICK [17]

Answer:

%C = 56,1%

%H = 5,5%

%Cl = 27,6%

%N = 10,8%

Explanation:

The moles of CO₂ are the same than moles of C in the herbicide.

Moles of H₂O are ¹/₂ of moles of H in the herbicide.

Moles of CO₂ are obtained using:

n = PV/RT

Where, in STP: P is 1 atm; V is 0,2092L; R is 0,082atmL/molK; T is 273 K

moles of CO₂ are: 9,345x10⁻³ mol≡ mol of C×12,01g/mol = <em>0,1122 g of C ≡ 112,2mg of C</em>

In the same way, moles of H₂O are 5,450x10⁻³mol×2 =0,1090 mol of H×1,01g/mol = <em>0,0110 g of H ≡ 11,0mg of H</em>

As you have 55,14 mg of Cl, the mg of N are:

200,0mg - 112,2 mg of C - 11,0 mg of H - 55,14 mg of Cl = 21,66 mg of N

Thus, precent composition of the herbicide is:

%C = \frac{112,2 mgC}{200,0mg}×100 = 56,1%C

%H = \frac{11,0 mgH}{200,0mg}×100 = 5,5%H

%Cl = \frac{55,14 mgCl}{200,0mg}×100 = 27,6%Cl

%N = \frac{21,66 mgN}{200,0mg}×100 = 10,8%N

I hope it helps!

3 0
3 years ago
Other questions:
  • Post your responses to the following:
    9·1 answer
  • How many molecules are in 7.90 moles of CH4?
    12·1 answer
  • Which of the following is the best example of a hypothesis?
    12·1 answer
  • I NEED THE ANSWER ASAP, GIVING BRAINLIEST.
    15·2 answers
  • How many moles are in 2.23 X 10^50 molecules of H2?
    6·1 answer
  • Which set is an example of an element, a compound, and a mixture?
    6·1 answer
  • Match the procedural step to its purpose in the written procedure for the Fischer esterification of benzoic acid with methanol i
    6·1 answer
  • What is the pOH of a solution with an OH- ion concentration of 8.4E-7?
    13·1 answer
  • 54:63 ratio simplest form?
    11·1 answer
  • How many milliliters of 0. 15 m solution could you prepare?.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!