Solubility is defined as the amount of a substance that can dissolve in a given amount of solvent. If enough substance is dissolved then the solution is defined as saturated, however, if more of the substance is able to be dissolved then it is considered an unsaturated solution. Temperature affects solubility in different ways, for gases dissolved in water it will decrease with an increase in temperature, in other words, cold water will dissolve more gas than hot water can. Polarity also affects solubility polar molecules are able to dissolve more easily in polar solutions and nonpolar molecules dissolve more readily in nonpolar solutions. As such, the answer to this question is D, the pressure above the solution does not affect solubility. The reason for this is that with a change in pressure there is litter to no change in solubility for solids or liquids, however, gasses as being the exception to most rules, their solubility increases as pressure increases.
Answer:
A central C is double bonded to an O, and single bonded to 2 H
Explanation:
Methanal, also known as formaldehyde, is a chemical compound used to preserve dead biological specimens for further study. It is called formalin when in a solution and it helps keep specimens in a fresh state by hardening the tissues of the specimen involved.
Formaldehyde is a gaseous compound that has an aldehyde functional group i.e. -CHO and has a chemical formula, H-CHO or CH2O as described in the question that a central C is double bonded to an O, and single bonded to 2 H (see attached image for structural formula).
Answer:
Molar percent of sodium in original mixture is 88,50%
Explanation:
The last reaction is:
BaCl₂ + Na₂SO₄ → BaSO₄ + 2 NaCl
The moles of BaCl₂ are:
0,132L × 3,80M = 0,502 moles of BaCl₂
As the amount of BaCl₂ is the maximum possible to produce BaSO₄, the moles of BaCl₂ must be the same than moles of Na₂SO₄.
0,502 moles of BaCl₂ ≡ 0,502 moles of Na₂SO₄
These moles of Na₂SO₄ comes from:
2 Na + H₂SO₄ → Na₂SO₄ + H₂
As the reaction is in stoichiometric amounts, moles of Na are twice the moles of Na₂SO₄
0,502 moles of Na₂SO₄ ×
× 22,99 g/mole = 23,08 g of Na
Molar percent of sodium in original mixture is:
= <em>88,50% </em>
I hope it helps
Answer:
B. More reactant is added.
Explanation:
The question basically asks at which condition would the forward reaction be favoured.
The law of equilibrium states when a system at equilibrium is disturbed by, it would annul that change. In order to increase the forward reaction, more of the reactant should be added. In order to annul this change, the system would have to favour the reaction that deals with reducing the amount of reactant added.
The correct option is;
B. More reactant is added.
