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MatroZZZ [7]
3 years ago
11

¿como afecta la temperatura el volumen de un gas?

Chemistry
1 answer:
Oxana [17]3 years ago
8 0

Lo afect porque cuando la temperature aumenta, el volumen aumentará, luego, cuando we mantiene la presión, es constante. Calentar el gas aumenta la emergía cinética we law partículas, lo que have que el gas se expanda.

Espero que esto ayude :)

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Less energy was entering Earth's
ololo11 [35]

Answer:

The temperatures on Earth increase

Explanation:

more energy results in more heat.

6 0
3 years ago
Which action by the British government was
Lera25 [3.4K]
The answer is (4) taxing the colonies without representation in Parliament

This set off the Revolutionary War, and the slogan "no taxation without representation" became famous.
3 0
4 years ago
(image attached)
Naily [24]

Answer:

D) He did not multiply the chlorine and oxygen atoms by the coefficient 4.

Explanation:

The coefficient 4 at the beginning of the chemical formula indicates that there are four Ca(ClO3)2 molecules. Think of this as Ca(ClO3)2 × 4. This means that he had to multiply the number of atoms for each element by 4 as well, so he should've ended up with 4 total calcium atoms (which is correct), 8 total chlorine atoms, and and 24 total oxygen atoms. He did not get all these answers because he didn't multiply the chlorine and oxygen atoms by the coefficient 4.

8 0
3 years ago
Read 2 more answers
A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of
mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.125

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.125=e^{-0.00440\times t}

t = 473 year

8 0
3 years ago
3.) 2.46 grams of Cu(NO3)2 would contain how many formula units?
RUDIKE [14]

Answer:

7.90×10²¹ formula units

Explanation:

From the question given above, the following data were obtained:

Mass of Cu(NO₃)₂ = 2.46 g

Formula units of Cu(NO₃)₂ =?

From Avogadro's hypothesis,

1 mole of Cu(NO₃)₂ = 6.02×10²³ formula units

Next, we shall determine the mass of 1 mole of Cu(NO₃)₂. This can be obtained as follow:

1 mole of Cu(NO₃)₂ = 63.5 + 2[14 + (3×16)]

= 63.5 + 2[14 + 48]

= 63.5 + 2[62]

= 63.5 + 124

= 187.5 g

Thus,

187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units

Finally, we shall determine the formula units contained in 2.46 g of Cu(NO₃)₂. This can be obtained as follow:

187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units.

Therefore,

2.46 g of Cu(NO₃)₂ =

(2.46 × 6.02×10²³)/187.5

= 7.90×10²¹ formula units

Thus, 2.46 g of Cu(NO₃)₂ contains 7.90×10²¹ formula units

7 0
3 years ago
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