Answer:
T = 0.607 seconds
Explanation:
Given:
Mass, M = 1.50 × 10⁻² kg
Radius, R = 5.50 × 10⁻² m
Now,
the time period in terms of moment of inertia is given as:
.....................1
where, T is the time period
g is the acceleration due to gravity
I is the moment of inertia
Now,
Moment of inertia, I is given as:

on substituting the moment of inertia in the equation 1, we get

or

on substituting the valeus, we get

or
T = 0.607 seconds
Hence, the time period is 0.607 seconds
Answer:
. living things only have energy : true.
Answer: T = 472.71 N
Explanation: The wire vibrates thus making sound waves in the tube.
The frequency of sound wave on the string equals frequency of sound wave in the tube.
L= Length of wire = 26cm = 0.26m
u=linear density of wire = 20g/m = 0.02kg/m
Length of open close tube = 86cm = 0.86m
Sound waves in the tube are generated at the second vibrational mode, hence the relationship between the length of air and and wavelength is given as
L = 3λ/4
0.86 = 3λ/4
3λ = 4 * 0.86
3λ = 3.44
λ = 3.44/3 = 1.15m.
Speed of sound in the tube = 340 m/s
Hence to get frequency of sound, we use the formulae below.
v = fλ
340 = f * 1.15
f = 340/ 1.15
f = 295.65Hz.
f = 295.65 = frequency of sound wave in pipe = frequency of sound wave in string.
The string vibrated at it fundamental frequency hence the relationship the length of string and wavelength is given as
L = λ/2
0.26 = λ/2
λ = 0.52m
The speed of sound in string is given as v = fλ
Where λ = 0.52m f = 295.65 Hz
v = 295.65 * 0.52
v = 153.738 m/s.
The velocity of sound in the string is related to tension, linear density and tension is given below as
v = √(T/u)
153.738 = √T/ 0.02
By squaring both sides
153.738² = T / 0.02
T = 153.738² * 0.02
T = 23,635.372 * 0.02
T= 472.71 N
The body moves at a velocity of 1.62m/s after the bullet emerges.
<h3>Given:</h3>
Mass of bullet,
= 22g
= 0.022 kg
Mass of the block,
= 1.9 kg
Velocity of bullet ,
= 265 m/s

According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.
After penetration;


The formula for calculating the collision of a body is expressed as:
p = mv
m is the mass of the body
v is the velocity of the body
∴ Momentum before = Momentum after
Substitute the given parameters into the formula as shown:

Therefore, It moves with a velocity of 1.62 m/s.
Learn more about momentum here:
brainly.com/question/25121535
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Answer:
False
Explanation:
Think of the electric potential in terms of potential energy. If you imagine a place with high elevation (A) and another one at sea level (B), a ball will roll from high potential to low potential (A-->B).
Everything in our universe wants to reach a lower state of energy if no external force is acted upon it. Every object tends to slow down (friction), a radioactive element dissipates energy (an unstable element releases energy to get to a stable state), water in the clouds comes down to the ground (rain experiencing difference in potential energy).
Electric potential is exactly the same, you just can't see it! It flows from higher voltage (which is a synonym for electric potential) to lower voltage.