What is the answer for 24-9/12

Mathematics

1 answer:

kvasek [131]3 years ago

6 0

Answer= 94/4

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For this set of data,<br> 89, 88, 84, 87, 89, 84, 84, 83, 85, 89, 84<br> Find the standard deviation

Ilia_Sergeevich [38]

Answer: 2.2962419891482

Step-by-step explanation: First get the mean of the numbers or the average

the mean in this case is 86

then subtract each number by the mean of 86

the numbers then become : 3, 2, -2, 1, 3, -2, -2, -3, -1, 3, -2

then square all the numbers to get : 9, 4, 4, 1, 9, 4, -4, 9, 1, 9, 4

then find the mean of those numbers which is 5.2727272727273

then find the square root of this number to find the standard deviation

2.2962419891482 is the standard deviation

hope this helps mark me brainliest if it helped

6 0

3 years ago

Nikita invests $2,000 into a bank account with a 4% annual interest rate. In seven years, which is the most expensive item she c

Stella [2.4K]

Answer:

Anything that does not cost more than $2,560.00

Step-by-step explanation:

Provided that Nikita is spending money that she had invested and the amount she collected over the period of 7 years. She can buy any item that costs no more than $2,560.00 but how?

It is a problem of simple interest:

Here the principal amount (P) = $2,000.00

Interest rate (r) = 4%

Time period (t) = 7 years

So, total amount that she would get by the end of 7 years is:

$A=P+SI$

$SI=\frac{P\times r\times t}{100}$

Plugging the values we get:

$SI=\frac{2000\times 4\times 7}{100}=560.00$

So the interest collected over 7 years is $560.00

Therefore, the total amount after 7 years is:

$\$2000.00+\$560.00=\$2,560.00$

If Nikita is using this money then the most expensive item that she could buy will cost no more than $2,560.00.

6 0

3 years ago

Nth Term help please

liberstina [14]

$\bf \begin{array}{|ll|ll} \cline{1-2} term&value\\ \cline{1-2} a_1&3\\[0.8em] a_2&\stackrel{3\cdot 2}{6}\\[0.8em] a_3&\stackrel{6\cdot 2}{12}\\[0.8em] a_4&\stackrel{12\cdot 2}{24}\\[0.8em] a_5&\stackrel{24\cdot 2}{48}\\[0.8em] a_6&\stackrel{48\cdot 2}{96} \\ \cline{1-2} \end{array}$