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mixer [17]
3 years ago
8

What is the value of a when we rewrite (6/17)^9 x as a^x

Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

a = 8.498\times 10^{-5}

Step-by-step explanation:

The value of a is obtained herein:

\left(\frac{6}{17} \right)^{9\cdot x}

\left[\left(\frac{6}{17} \right)^{9}\right]^{x}

\left(8.498\times 10^{-5} \right)^{x}

a = 8.498\times 10^{-5}

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<em>I think, to start out, we could set up the problem like so</em>

<em>15 + t ≥ 26</em>

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<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>

<em>t ≥ 11</em>

<em>So the resulting answer is t ≥ 11.</em>

<em />

<em>I hope that my interpretation helps.</em>

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8 0
2 years ago
Read 2 more answers
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Gnoma [55]

Answer:

x=-10

Step-by-step explanation:

reorder the terms: 8+2x=18+3x

solve: 8+2x=18+3x

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-1 -1

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3 0
2 years ago
ASAP! what numbers round to 756,000 using 2,5,5,8,6, and 2?
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3 years ago
A customer brings a box with a mix of integers as inputs to a function machine. She wants you to program a function machine so t
Natasha_Volkova [10]

Answer:

The manager did not make a good suggestion.

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