What is the value of a when we rewrite (6/17)^9 x as a^x

Mathematics

1 answer:

Ksju [112]2 years ago

8 0

Answer:

$a = 8.498\times 10^{-5}$

Step-by-step explanation:

The value of $a$ is obtained herein:

$\left(\frac{6}{17} \right)^{9\cdot x}$

$\left[\left(\frac{6}{17} \right)^{9}\right]^{x}$

$\left(8.498\times 10^{-5} \right)^{x}$

$a = 8.498\times 10^{-5}$

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Which exponential function is represented by the values in the table?

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$\displaystyle f(x)=4\cdot\left(\frac{1}{2}\right)^x$

Step-by-step explanation:

<u>Exponential Function</u>

The exponential function can be written with the general equation:

$f(x)=A\cdot r^x$

Where A is the value when x=0 and r>0 is the ratio. If r is greater than 1, the function is increasing, if r is less than 1, the function is decreasing.

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