Question

3kg ball traveling at 10 m/s east collides with 5 kg ball traveling at 2m/s east after the collision the balls stick together what is the final velocity of the 3kg ball ?

Answer 1

Answer:

Explanation:

The formula for this is designed around the fact that momentum must be conserved:

$[(m_{ball1}*v_{ball1})+(m_{ball2}*v_{ball2})]_b=[(m_{ball1}+m_{ball2})v_{both}]_a$

This is because they sitck together after they collide. Filling in:

[(3*10)+(5*2)] = [3 + 5]v and

30 + 10 = 8v so

40 = 8v and

v = 5

They are both moving east at a velocity of 5 m/s since they stuck together.