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Alona [7]
3 years ago
11

Please answer this question :)

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0
Answer: 2.663043987
explanation: use calculator
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What is the common ratio of the geometric sequence below 10,15,22.5,33.75​
snow_lady [41]

Answer:

You divide each member by the one before it

Explanation:

You'll find that the answer  r = 1.5  ( r  for ratio)

The first term is called  u∧0 = 10

So the<em>  n</em> th term is called  u <em>n </em>− 1  and it takes <em> n</em> − 1  multiplications to get there from u 0 , so:

<em>n </em>th term =  u n  − 1  = u 0 ×  r n − 1

Or, in your case: <em> n</em> th term  = u <em>n </em>− 1 = 10 × 1.5<em> n </em>− 1

you can check out this it has the same answer as me

https://socratic.org/questions/how-do-you-find-the-nth-term-rule-for-10-15-22-5-33-75-50-63

6 0
3 years ago
I’m confused 273 - 75 = 280 - 82
Sati [7]

Answer: Both answers equal 198

Step-by-step explanation:

While at first this problem may look weird and even stump you. However, break it up.

What is 273-75? 198

What is 280-82? 198

The reason both equation equals each other are because both have the same answer.

Another example problem: 100-1=26+73

100-1= 26+73

100-1 = 99

26+73 = 99

5 0
3 years ago
Read 2 more answers
Marty has saved $63. He spent $3 on a video rental. Write a ratio as a fraction in simplest form to represent what portion of hi
igomit [66]
<span>Marty has saved = $63
</span><span>He spent on a video rental = $3
Remaining money he saved = $63 - $3 = $60
</span><span>portion of his savings left = 60/72 = 30/36 = 5/6
</span>Thus the answer is 5/6 or 5:6
5 0
3 years ago
Read 2 more answers
Simplify the following expression.
VladimirAG [237]

Answer:

B.

Step-by-step explanation:

It is just common sense. The top numbers have to be smaller than the top numbers

7 0
4 years ago
Help please lol thankssss
Natali [406]

Answer:

1. 60

2. 36

6. 57

Step-by-step explanation:  For number 2 and 6 I subtracted the numbers by 90 because one side of the triangle is 90 degrees.

6 0
3 years ago
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