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Mathematics

2 answers:

harkovskaia [24]2 years ago

8 0

Is this Morse code ......

MAVERICK [17]2 years ago

4 0

Answer:

nice picture bro

Step-by-step explanation:

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Rewrite the expression as a single power with a negative exponent

goblinko [34]

$~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ \left(\cfrac{1}{3}\cdot \cfrac{1}{3}\cdot \cfrac{1}{3}\cdot \cfrac{1}{3} \right)^2\implies \left[ \left( \cfrac{1}{3} \right)^4 \right]^2\implies \left( \cfrac{1^4}{3^4} \right)^2 \\\\\\ \left( \cfrac{1^{4\cdot 2}}{3^{4\cdot 2}} \right) \implies \cfrac{1}{3^8} \implies 3^{-8}$

let's recall that

$\begin{array}{llll} 1^1&=&1\\ 1^{10}&=&1\\ 1^{1,000}&=&1\\ 1^{1,000,000,000}&=&1\\ 1^{1,000,000,000,000}&=&1\\ \end{array}$

8 0

2 years ago

Apply the junction rule to the junction labeled with the number 1 (at the bottom of the resistor of resistance R2R2R_2). Answer

Ira Lisetskai [31]

Answer:

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Step-by-step explanation:

The image of the circuit is obtained online and attached to the question.

The junction rule is essentially a law of conservation of current (charges). It applies to electrical circuits at steady state.

It explains that the for any given junction (node in an electrical circuit), the sum of current entering the junction is equal to the sum of current leaving the junction. That is, the net sum of current at any junction is zero.

Current entering a junction is assigned a positive sign and that leaving the junction is assigned a negative sign.

Σ I = 0

From the image of the circuit attached, I₁ is leaving the junction labelled number 1 and I₂ and I₃ are entering the junction.

Hence,

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Hope this Helps!!!