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Strike441 [17]
3 years ago
5

Heat being transferred from a hot pan to our food while cooking is an example of... *

Chemistry
1 answer:
stellarik [79]3 years ago
6 0

A.conduction  i hope it helps

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How were atomic models developed when no one had seen an atom?
AnnyKZ [126]
Atomic models were developed through indirect observation even though no one had seen an atom. There were many experiments of which I know nothing about, but in the end the scientists managed to come up with a formula and various models to describe atoms. 
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3 years ago
How are monosaccharides and polysaccharides structurally different? *NO PLAGIARISM PLS*
Mariana [72]

Explanation:

Monosaccharides are simple carbohydrates that cannot be further hydrolyzed to simpler carbohydrates. They contain between three and six carbon atoms per molecule.

Polysaccharides  are complex carbohydrates . They are condensation polymers derived from very long chains of monosaccharide units.

Structurally, polysaccharides are made up of repeating units of monosaccharides.

3 0
3 years ago
Read 2 more answers
1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

___________________________________

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

3 0
3 years ago
G- how many grams of f2 gas are there in a 5.00-l cylinder at 4.00 × 103 mm hg and 23°c?
aniked [119]
<span>PV = nRT (4000 Torr)(5 L) = n (62.4 Torr-L/mol-K)(296K) n = 1.08 moles 28 g/mol, 1.08 moles = 30.3 grams your answer is C.30.3 g</span>
6 0
3 years ago
What is the mass, in grams, of 0.125 L of CO2 at STP? Question 4 options: 2.80 g 181 g 0.246 g 4.11 g
Zolol [24]
1) Use the fact that 1 mol of gas at STP occupies 22.4 liter

=> 1 mol / 22.4 l = x / 0.125 l => x = 0.125 l * 1 mol / 22.4 l = 0.00558 mol

2) Now use the molar mass of the gas

molar mass of CO2 ≈ 44 g / mol

Formula: molar mass = mass in grams / number of moles =>

mass in grams = molar mass * number of moles = 44 g/mol * 0.00558 moles

mass = 0.246 g

Answer: 0.246 g
7 0
3 years ago
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