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Triss [41]
3 years ago
14

Consider the following first order decomposition reaction with a half-life of 65 seconds at a given temperature:

Chemistry
1 answer:
katrin [286]3 years ago
6 0

Answer:

130

Explanation:

This is because that 3atm of N2O4 is used up for the 6atm of NO2, so 1 atm N2O4 is left. Resulting in In(1/4).

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Which of the following is a noble gas? carbon dioxide, boron, oxygen, and helium
sweet [91]
Carbon dioxide is a noble gas.
4 0
3 years ago
Read 2 more answers
How many Cl atoms are in Zn(ClO3)2?<br> O A. 2<br> O B. 1<br> O c. 3<br> O D. 6
White raven [17]
The answer cl atoms are in zn(cio3)2 is A:2 because I looked it up and it gave me 2.
3 0
3 years ago
Calculate the enthalpy change (in joules) involved in converting 5.00 grams of water at 14.0 °c to steam at 115 °c under a const
tensa zangetsu [6.8K]

Enthalpy change is the term given to the concentration of the heat absorbed or evolved in a reaction carried out at a constant pressure. It is given by the symbol ΔH.

Enthalpy change = m (Cwater × dT + Hvap + Csteam × dT

dHvap = 40.67 kJ/mol = 40.67 × 103/18 = 2259.4 J/g

Enthalpy change = 5.00 [4.18 × (100-14) + 2259.4 + 1.84 × (115-100)]

= 13232.4 J

7 0
3 years ago
If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?
Yanka [14]

Answer:

204g of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.

Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:

Number of mole of NH3 = 12 moles.

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar mass

Mass of NH3 = 12 x 17

Mass of NH3 = 204g.

Therefore, 204g of NH3 will be produced from the reaction.

3 0
3 years ago
A. 207 kJ<br> B. 4730 kJ<br> O C. 9460 kJ<br> O D. 414 kJ
slavikrds [6]

Answer:

C = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

by putting values,

Q= 2kg ×  4730 Kj/Kg

Q = 9460 Kj

3 0
3 years ago
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