Since the rock as been dropped off the building you can assume that initial velocity equals 0m/s.
t=4.5s
acceleration due to gravity=9.8m/s^2
s=ut+1/2at^2
Since u=0, s=1/2at^2
s=1/2(9.8)(4.5)^
s=99.225m
The centripetal force is the gravitational force of attraction between the Earth and the Moon.
Also, the gravitational force of attraction between the Earth and the Sun is the centripetal force that causes the Earth to stay in orbit around the Sun.
Also, the gravitational force of attraction between a TV satellite, a weather satellite, or a GPS satellite and the Earth is the centripetal force that causes each satellite to stay in orbit around the Earth.
Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
<em>Answer:</em>
<em>The answers are: </em>
- <em>A-which is the image is always right side up.</em>
- <em>E-the image is virtual</em>
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<em>Explanation: MY EXPLANATION IS YOU ARE WELCOME BIG DOG 100..</em>
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Answer:
317.52 mi/hr
Explanation:
First convert Meters into miles as the answer is required in miles/ h
1000m = 0.62 mi
Now, convert second into hours
7.45s = 0.0001 hr
The speed of the boat would be
v = 0.62/0.0001
=317.52 mi/hr