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bixtya [17]
3 years ago
7

Gene invested $500 at 8% interest compounded quarterly. how much is in the account after 1 year?

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
$5412.22
 
Use the formula A=P(1+r/n) to the n times t power

P= initial investment 500
r= Rate 8% change to decimal .08
n= number of times compounded which is quarterly so 4
t= time which is just 1 for one year
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One number is 4 times as large another. The sum of their reciprocals is 45/4. Find the two numbers
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Let, 
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According to the question,
x = 4y ......................................................equation (1)

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Taking equation (2)
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Substituting the value of "x" from equation (1), we get,

\frac{1}{(4y)} + \frac{1}{y}= \frac{45}{4}

\frac{1}{4y} + \frac{1}{y}* \frac{4}{4} = \frac{45}{4}

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\frac{1+4}{4y} = \frac{45}{4}

\frac{5}{4y} = \frac{45}{4}

Cross multiplying, we get,

5*4 = 45*4y

20 = 180y
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\frac{20}{180}  = y

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Now,
Taking equation (1)
x = 4y
Substituting the value of "y", we get

x = 4( \frac{1}{9} )

x= \frac{4}{9}

So, the numbers are \frac{1}{9} and \frac{4}{9}

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UNO [17]
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