Given:
The center of the circle = (-2,1).
Circle passes through the point (-5,3).
To find:
The equation of the circle.
Solution:
Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).




On further simplification, we get


The standard form of a circle is:

Where, (h,k) is the center of the circle and r is the radius of the circle.
Substitute h=-2, k=1 and
.


Therefore, the equation of the circle is
.