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gogolik [260]
3 years ago
14

Anyone plsss helpppp meeee

Mathematics
1 answer:
dusya [7]3 years ago
5 0

Answer:

47 to 63 because that is the range of the standard deviation.

Hope this helps and brainliest please

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Which of the following is not equivalent to 1/25?
taurus [48]
 The answer is D. 5^-2 times 5^4.
3 0
3 years ago
Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

3 0
1 year ago
Read 2 more answers
HELP PLEASE HURRY!!!!!!!!!!!!!
valentina_108 [34]

Answer:

i would say its b

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Sin A 4/5.<br><br> Find<br> COSA + tan A
Ivahew [28]

Answer:

Step-by-step explanation:

The opposite side (the one not connected to A) = 4

The hypotenuse is 5

The adjacent side needs to be found for the cosine and the tangent.

a^2 + b^2 = c^2

a = opposite side = 4

b = adjacent side = ?

c = hypotenuse = 5

4^2 + x^2 = 5^2

16 + x^2 = 25          

x^2 = 25 - 16

x^2 = 9

x = sqrt(9)

x = 3

cos(A) = adjacent / hypotenuse = 3/5

Tan(A) = opposite / adjacent = 4/3

cos(A) + tan(A) = 3/5 + 4/3

cos(A) + tan(A) = 9/15 + 20/15 = 29/15

4 0
3 years ago
Read 2 more answers
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the
Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

(AB)^2=(BC)^2+(AC)^2

(13)^2=(BC)^2+(5)^2

169=(BC)^2+25

BC=12

\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin A=\frac{BC}{AB}

A=\sin ^{-1}\frac{12}{13}

A=67.38

Bisector divides the angle in two equal parts, therefore,

A'=\frac{67.38}{2} =33.69

In triangle ACD.

\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}

\cos A'=\frac{AC}{AD}

\cos (33.69^{\circ})=\frac{5}{AD}

0.832=\frac{5}{AD}

AD=\frac{5}{0.832} =6.009\approx 6.01

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0
3 years ago
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