It increased by 3000$ for every 200,000$ increased in appraised value. Hope this helps❤️please rate
Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
Answer: B
The piece wise functions first part says: x is less than it equal to one and has a vertical shift down 4. which would mean the circle is closed and shaded down.
The second part of the function says x is greater than one and has a vertical shift up 3. This would mean it is an open circle and is shaded up.
Answer:
the x axis is 10, its interpretation is actually G, so on a graph instead of X and Y you would have G and T
Answer:
The other solution of the given equation x² + bx + c = 0 is also rational number.
Step-by-step explanation:
Here, given: ax² + bx + c = 0 is a quadratic equation
Also, one solution (r) of equation is RATIONAL.
To show: The other solution (s) is also RATIONAL
Now, here: as x² + bx + c = 0
Since r and s are the two given solutions, the given equation can be factorized as:
x² + bx + c = (x -r) (x - s)
Simplifying LHS, we get:
(x -r) (x - s) = x x - r (x) - s (x) + (r)(s)
= x² + x(-r - s) + rs
or, x² + bx + c = x² + x(-r - s) + rs
Comparing the related terms, we get:
b = (-r - s)
⇒ b + s = - r
or, s = -r - b
Now, given : r = Rational and the negative of a rational is also rational.
⇒ -r is also rational
Also, difference of two rational number is also rational.
⇒ -r - b is also rational
⇒ s is a RATIONAL NUMBER
Hence, the other solution of the given equation x² + bx + c = 0 is also rational number.
