1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mafiozo [28]
3 years ago
11

Which of the following is n application of electromagnetic field? A. D. C motor B. A.C motor C. Moving coil galvanometer D. All

of the bov​
Physics
1 answer:
Zanzabum3 years ago
4 0

Answer:

c or d

Explanation:

it just is thats how it is

You might be interested in
An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has t
Lena [83]

Explanation:

The De-Broglie wavelength in terms of potential difference is given by:

\lambda=\dfrac{h}{\sqrt{2meV} }

Where,

h is Planck's constant

m is mass of charged particle

V is potential difference

e is the amount of charge

It means that the De-Broglie wavelength is inversely proportional to the mass.

Since, the mass of the proton is more than the mass of the electron. So, the De- Broglie wavelength of the electron is larger than proton.

3 0
3 years ago
One of the best candidates for a black hole is found in the binary system called A0620-0090. The two objects in the binary syste
Darya [45]

Answer:

One of the best candidates for a black hole is found in the binary system called A0620-0090. The two objects in the binary system are an orange star, V616 Monocerotis, and a compact object believed to be a black hole. The orbital period of A0620-0090 is 7.75hours, the mass of V616 Monocerotis is estimated to be .67 times the mass of the sun, and the mass of the black hole is estimated to be 3.8 times the mass of the sun. Assuming that the orbits are circular, find the radius of the orbit of the orange star.

Explanation:

6 0
3 years ago
Pls help with either of these I will give up brainliest
Contact [7]

Answer:

1. The bird close to the center

2. 4/25 of the original force.

Explanation:

1. Tangential velocity is v=w*d (in m/s), where w is the rotational speed, commonly denoted as the letter omega (in radians per second). d is the distance from the center of the rotating object to the position of where you would like to calculate the velocity (in meters).

As we can note, the furthest from the center we are calculating the velovity the higher it is, because the rotational velocity is not changing but the distance of the object with respect to the center is. If v=w*d, then the lower the d (distance) the lower the tangential velocity.

2. Take a look at the picture:

We have the basic equation for the gravitational force.

We have to forces: Fg1, which is the original force, and Fg2, the force when the mass and the distance changes.

If we consider that mass 2 didn't change (m2'=m2), mass 1 is four times its original (m1'=4*m1) and distance is 5 times the original (r'=5*r), then next step is just plugging it into the equation for Fg2.

Dividing the original force Fg1 by the new force Fg2 (notice you can just as well do the inverse, Fg2 divided by Fg1) gives us the relation between the forces, cancelling all the variables and being left only with a simple fraction!

6 0
3 years ago
20 POINTS!!!
hram777 [196]
I think its inductance. If its not then I think its none of the above
5 0
3 years ago
A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a
Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

m_1v_1+m_2v_2 = (m_1+m_2)V_f

Where,

m_{1,2}= Mass of each object

v_{1,2}= Initial Velocity of Each object

V_f= Final Velocity

Our values are given as

m_1 = 2190Kg

v_1 =10.5m/s

m_2 = 3220kg

V_f = 4.74m/s

Replacing we have that

m_1v_1+m_2v_2 = (m_1+m_2)V_f

(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)

v_2 = 0.8224m/s

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0
4 years ago
Other questions:
  • Describe the characteristics of certain plants, such as grasses, that enable them to be distributed widely in an environment
    15·1 answer
  • We say that visible light has wavelength from 400nm to roughly 800nm. What is the biggest "energy-jump" (excited) for an atom if
    5·1 answer
  • You are in a fire truck heading directly toward a tunnel in a mountainside at 17m/s. you hear the truck's 90Hz siren as well as
    15·1 answer
  • The main difference between speed and velocity involves
    13·1 answer
  • When chemical energy is released, what is formed?
    13·1 answer
  • A model of a spring/mass system is 4x'' + e−0.1tx = 0. By inspection of the differential equation only, discuss the behavior of
    9·1 answer
  • A car has wheels which spin forwards. As the wheels spin forwards, they grip the road and push the road backwards. Since forces
    13·2 answers
  • Identifying Obstacles
    15·1 answer
  • A force in the opposite direction<br> of the motion
    14·1 answer
  • How does the composition of the layers affect the position of the layers?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!