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mafiozo [28]
3 years ago
11

Which of the following is n application of electromagnetic field? A. D. C motor B. A.C motor C. Moving coil galvanometer D. All

of the bov​
Physics
1 answer:
Zanzabum3 years ago
4 0

Answer:

c or d

Explanation:

it just is thats how it is

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If a 2kg ball has and initial velocity of
lakkis [162]

Answer:

\boxed {\boxed {\sf 12 \ Newtons }}

Explanation:

Force is equal to the product of mass and acceleration.

F=m*a

We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.

1. Calculate Acceleration

Acceleration is the change in velocity over the change in time.

a=\frac{V_f-V_i}{t}

The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.

V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s

Substitute the values into the formula.

a=\frac{10 \ m/s-4 \ m/s }{1 \ s}

Solve the numerator.

a=\frac{6 \ m/s}{1 \ s }

Divide.

a= 6 \ m/s/s=6 \ m/s^2

2. Calculate Force

Now we know the acceleration and the mass.

m= 2 \ kg \\a= 6 \ m/s^2

Substitute the values into the fore formula.

F= 2 \ kg * 6  \ m/s^2

Multiply.

F= 12 \ kg*m/s^2

  • 1 kilogram meter per square second is equal to 1 Newton.
  • Our answer of 12 kg*m/s² is equal to 12 Newtons

F= 12 \  N

The force applies to the ball was <u>12 Newtons.</u>

8 0
3 years ago
(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How
OLEGan [10]

Answer:

(a) Current flowing through truck battery is 180 A

(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

The charge on the truck battery,q = 720 C

Time, t = 4.00 s

Consider I be the current flowing through truck battery.

The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

I=\frac{720}{4}

I = 180 A

(b) Given:

The charge on the calculator,q = 7.00 C

The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A

Consider t be the time.

The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

t=\frac{1}{0.3\times10^{-3} }

I = 333.33 s

8 0
4 years ago
Hey friends give me the solution to attachment​
skelet666 [1.2K]

Answer:

downwards bro now dodododododdodo

5 0
3 years ago
Read 2 more answers
Which property of metals allows corrosion to take place? reactivity malleability ductility conductivity Description
horrorfan [7]
Your best bet would be reactivity
7 0
3 years ago
Read 2 more answers
Ammonia enters the compressor of an industrial refrigeration plant at 2 bar, −10°C with a mass flow rate of 15 kg/min and is com
Juli2301 [7.4K]

Answer:

a) W=85.225 kW

b) 0.02\frac{kW}{K}

Explanation:

First, consider the energy balance for the compressor: The energy that enters to the system (W and enthalpy of the feed flow) is equal to the energy that goes out from it (Heat Q and enthalpy of the exit flow):

W+m*h_1=Q+m*h_2\\W=Q+m*(h_2-h_1)

Consider the enthalpy data from van Wylen 6th edition, Table B.2.2. According to that, h_1=h(200kPa,-10C)=1440.6\frac{kJ}{kgK},  h_2=h(1200kPa,140C)=1757.5\frac{kJ}{kgK}

So, the power input to the compressor is:

W=6kW+15\frac{kg}{min}*\frac{min}{60s}*(1757.5-1440.6)\frac{kJ}{kg}\\W=85.225kW

b) The differential entropy change dS for a reversible heat transfer dQ at a temperature T is:

dS=\frac{dQ}{T}

This equation can be integrated if the heat transfer surface temperature remains constant, which is the case, giving as a result:

S_2-S_1=\frac{Q}{T}=\frac{6kW}{300K}=0.02\frac{kW}{K}

6 0
3 years ago
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