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katovenus [111]
4 years ago
7

(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How

long does it take 1.00 C of charge to flow through a calculator if a 0.300 mA current is flowing?
Physics
1 answer:
OLEGan [10]4 years ago
8 0

Answer:

(a) Current flowing through truck battery is 180 A

(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

The charge on the truck battery,q = 720 C

Time, t = 4.00 s

Consider I be the current flowing through truck battery.

The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

I=\frac{720}{4}

I = 180 A

(b) Given:

The charge on the calculator,q = 7.00 C

The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A

Consider t be the time.

The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

t=\frac{1}{0.3\times10^{-3} }

I = 333.33 s

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Answer:

C

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Because everything on Earth falls at the same speed, the masses of the balls do not matter. Since the acceleration due to gravity is constant, their speeds will both be increasing at the same rate, and therefore the difference in speeds would remain constant until they hit the ground. Hope this helps!

5 0
3 years ago
A system does 506 kj of work, and loses 266 kj of heat to the surroundings. what is the change in internal energy of the system?
babunello [35]

Answer:

The change in internal energy of the system = -772kJ

Explanation:

Given :

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Change in internal energy = (-266KJ) + (-506KJ)

Change in internal energy = -722KJ

7 0
3 years ago
Read 2 more answers
ayo 20 m long is heated from a temperature of 5 degree celsius to 55 degree celsius if the change in length is 0.020 m calculate
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Answer:2 x 10^-5K^-1

Explanation:

The solution is in the attached file

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3 years ago
A hot-water stream at 80 ℃ enters a mixing chamber with a mass flow rate of 0.5 kg/s where it is mixed with a stream of cold wat
rewona [7]

Answer:

\dot{m_{2}}=0.865 kg/s

Explanation:

\dot{m_1}= 0.5kg/s

from steam tables , at 250 kPa, and at

T₁ = 80⁰C ⇒ h₁ = 335.02 kJ/kg

T₂ = 20⁰C⇒ h₂ = 83.915 kJ/kg

T₃ = 42⁰C ⇒ h₃ = 175.90 kJ/kg

we know

\dot{m_{in}}=\dot{m_{out}}

\dot{m_{1}}+\dot{m_{2}}=\dot{m_{3}}

according to energy balance equation

\dot{m_{in}}h_{in}=\dot{m_{out}}h_{out}

\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=\dot{m_{3}}h_{3}

\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=(\dot{m_{1}}+\dot{m_{2}})h_{3}\\(0.5\times 335.02)+(\dot{m_{2}}\times 83.915)=(0.5+\dot{m_{2}})175.90\\\dot{m_{2}}=0.865 kg/s

4 0
4 years ago
Two identical positive charges exert a repulsive force of 6.2 × 10−9 n when separated by a distance 3.7 × 10−10 m. calculate the
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F=k \frac{q_1 q_2}{r^2}
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q1 and q2 are the two charges
r is their separation

In this problem, the two charges are identical, so we can call them q1=q2=q, and the formula becomes
F=k \frac{q^2}{r^2}

Since we know the magnitude of the force and the separation between the two charges, we can re-arrange the equation to find the value of each charge:
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5 0
3 years ago
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