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GuDViN [60]
3 years ago
5

Need a quick answer please and thanks

Chemistry
1 answer:
Snezhnost [94]3 years ago
3 0
7.8 x 10^-3 = 0.0078 lb/qt

1lb = 454 g

0.0078 / 454 = 1.718061 x 10^-5 g/qt
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The Groups 1 and 2 on the periodic table contain what atom type?
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Non metals
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24 g of magnesium were burned in oxygen. The compound formed had a mass of 40 g. Explain why the mass had gone up.
DIA [1.3K]

Answer :

According to the law of conservation of mass, the mass of reactants must be equal to the mass of products.

The balanced chemical reaction is,

Mg+\frac{1}{2}O_2\rightarrow MgO

As we know that the molar mass of magnesium is 24 g/mole, the molar mass of O_2 is 32 g/mole and the molar mass of magnesium oxide is 40 g/mole.

From the given balanced reaction, we conclude that

As, 1 mole of magnesium react \frac{1}{2} mole of oxygen to give 1 mole of magnesium oxide.

So, the mass of Mg is 24 g, the mass of O_2=\frac{1}{2}\times 32=16g and the mass of MgO is 40 g.

That means 24 g of Mg react with 16 g O_2 to give 40 g of MgO.

8 0
3 years ago
Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction
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Answer:

0.185M sulfuric acid

Explanation:

Based on the reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

<em>1 mole of sulfuric acid reacts with 2 moles of KOH</em>

Initial moles of H₂SO₄ and KOH are:

H₂SO₄: 0.750L ₓ (0.470mol / L) = <em>0.3525 moles of H₂SO₄</em>

KOH: 0.700L ₓ (0.240mol / L) = <em>0.168 moles of KOH</em>

The moles of sulfuric acis that react with KOH are:

0.168mol KOH ₓ (1 mole H₂SO₄ / 2 moles KOH) = 0.0840 moles of sulfuric acid.

Thus, moles that remain are:

0.3525moles - 0.0840 moles = <em>0.2685 moles of sulfuric acid remains</em>

As total volume is 0.700L + 0.750L = 1.450L, concentration is:

0.2685mol / 1.450L = <em>0.185M sulfuric acid</em>

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Leopard seals are animals adapted to survive in the freezing conditions of Antarctica. Individual leopard seals vary in their di
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Answer:

B. Thicker layer of blubber

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For the leopard seals to survives this harsh environment, it must have a thicker layer of blubber

Blubber is a thick layer of fat. It is called the adipose tissues and found in most marine organisms.

  • This layer helps in insulating the body against heat loss.
  • By so doing, the animal is able to conserve internal heat.
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Earnest Rutherford discovered that the nucleus is this
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