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Grace [21]
3 years ago
10

What is the molar mass for Mg3(PO4)2?

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
4 0
The answer is 262.855g/mol
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Please I need help with questions 5-9 and it’s very hard and I’m struggling with it and if you need to see the picture big then
Serggg [28]
"the answer will be 0.00 "
3 0
2 years ago
Shifts in the rock layer locations cannot account for gaps in the rock record<br><br> true or false
vivado [14]

Answer: That would be false because it is the contact between two layers representing a gap in the geologic record, usually from the erosion of the layers which would normally be expected to appear.

Explanation:

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4 0
3 years ago
Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit
vfiekz [6]

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For H_2SO_4:-  

Mass of H_2SO_4 = 196 g

Molar mass of H_2SO_4 = 98 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{196\ g}{98\ g/mol}

Moles\ of\ Sulfuric\ acid= 2\ mol

According to the given reaction:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,  

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = 4\times 40\ g = 160 g</u>

7 0
2 years ago
Calculate the pH of a 0.50 M HIO. The Ka of hypoiodic acid, HIO, is 2.3x10–11.0.305.325.479.474.80
never [62]

Answer:

pH = 5.47

Explanation:

The equilibrium that takes place is:

HIO ↔ H⁺ + IO⁻

Ka = \frac{[H+][IO-]}{[HIO]} = 2.3 * 10⁻¹¹

At equilibrium:

  • [HIO] = 0.5 M - x
  • [H⁺] = x
  • [IO⁻] = x

<u>Replacing those values in the equation for Ka and solving for x:</u>

Ka=\frac{x^2}{0.5-x}=2.3*10^{-11} \\x^2=(2.3*10^{-11})(0.5-x)\\x^2=1.15*10^{-11}-2.3*10^{-11}x\\x^2+2.3*10^{-11}x-1.15*10^{-11}=0\\x=3.39*10^{-6}

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

7 0
3 years ago
Calculate the amount of formula units in 2.10 moles of MgCl₂
Eva8 [605]
MgqI% = the formula and mass for H20 and that should be your answer for water
5 0
3 years ago
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