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nirvana33 [79]
4 years ago
14

How do the number of protons in an atom affect the atom's identity?

Chemistry
1 answer:
fredd [130]4 years ago
6 0

Answer:

The number of protons in an atom define each individual element because the number of protons is the atomic number which is the defining property of an atom and never changes. The number of protons determines an atom's identity. For example, Oxygen has an atomic number of 8, so it has 8 protons, so no matter what ionic compound or molecule it's part of, every single Oxygen atom will always have 8 protons each.

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1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?
Kazeer [188]

1. Answer:

1.0 × 10–9 M OH–

Explanation:

pH = -Log[H+]

pOH = -Log[OH-]

But;

pH + pOH = 14

Therefore;

[H+] + [OH-] = 1.0 × 10^-14 M

Therefore;

[OH-] = 1.0 × 10^-14 M - (1.0 × 10^–5 M)

         = 1.0 × 10^-9 M OH–

2. Answer;

pH = 7.28

Explanation;

pH = -Log[H3O+]

Given;

[H3O+] = 5.2 × 10^–8 M

Therefore;

pH = - log [5.2 × 10^–8 M]

     = 7.28

The pH is 7.28

3 0
3 years ago
Read 2 more answers
Classify lead: Select one: C = compound HE = heterogeneous mixture S = homogeneous mixture/solution E = element
Ira Lisetskai [31]

Lead is an E (element) and can be found on the periodic table.

5 0
3 years ago
How many grams of carbon dioxide will be produced if 76.4 grams of
goldfiish [28.3K]

Answer:

Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.

Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.

Explanation:

MRK ME BRAINLIEST PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/08%3A_Quantities_in_Chemical_Reactions/8.04%3A_Limiting_Reactant_and_Theoretical_Yield

5 0
3 years ago
What is the total E associated with one mole of photons (a unit known as the Einstein) of 3.91x1019 Hz?
sashaice [31]

Answer:

        E=1.56\times 10^{10}J

Explanation:

The<em> energy of a photon</em>, E, can be calculated with the Planck-Einstein equation:

          E=hf

Where:

  • h is Planck's constant 6.626×10⁻³⁴ J.s, and
  • f is the frequency of the photon or electromagnetic radiation.

Substituting with your data:

          E=6.626\times 10^{-34}J.s\times 3.91\times 10^{19}s^{-1}=2.5908\times 10^{-14}J

Now multiply by Avogadro's number to obtain the energy of one mole of photons:

          E=2.5908\times 10^{-14}J\times 6.022\times 10^{23}=1.56\times 10^{10}J

8 0
3 years ago
In the compound AbO3, the ratio of aluminum to<br> oxygen is
jasenka [17]
The compound is Al2O3. The ratio of aluminum to oxygen is 2:3.
3 0
3 years ago
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