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3 years ago

How do the number of protons in an atom affect the atom's identity?

Chemistry

1 answer:

fredd [130]3 years ago

6 0

Answer:

The number of protons in an atom define each individual element because the number of protons is the atomic number which is the defining property of an atom and never changes. The number of protons determines an atom's identity. For example, Oxygen has an atomic number of 8, so it has 8 protons, so no matter what ionic compound or molecule it's part of, every single Oxygen atom will always have 8 protons each.

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Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac

GalinKa [24]

<h2>a) The rate at which $NO_2$ is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen $O_2$ is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$ = 0.066 M/s

Rate in terms of disappearance of $O_2$ = $-\frac{1d[O_2]}{dt}$

Rate in terms of appearance of $NO_2$ = $\frac{1d[NO_2]}{2dt}$

1. The rate of formation of $NO_2$

$-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}$

$\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s$

2. The rate of disappearance of $O_2$

$-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}$

$-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

Learn more about rate law

brainly.com/question/13019661

https://brainly.in/question/1297322

7 0

3 years ago

__Zn(s)+__CuSO4(aq)--->_______+________

stiks02 [169]

Answer:

Zn + CuSO4 —> ZnSO4 + Cu

Explanation:

Zn is higher than Cu in electrochemical series and so will displaces Cu in solution according to the equation:

Zn + CuSO4 —> ZnSO4 + Cu

5 0

3 years ago

What safety precautions are needed when running a brine electrolysis plant

nikdorinn [45]

Good ventilation as a product of it is pure Cl2 gas

4 0

3 years ago

The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21 x 10-8 cm. What is this distance in inche

Sergio [31]

Answer:

$d=4.75\times 10^{-9}\ \text{inches}$

Explanation:

Given that,

The distance between the centers of the two oxygen atoms in an oxygen molecule is $1.21\times 10^{-8}\ cm$ .

We need to convert this distance in inches.

We know that,

1 cm = 0.393 inches

We can solve it as follows :

$1.21\times 10^{-8}\ cm=0.393\times 1.21\times 10^{-8}\\\\=4.75\times 10^{-9}\ \text{inches}$

So, the distance between the centers of the two oxygen atoms is $4.75\times 10^{-9}\ \text{inches}$ .

5 0

3 years ago

93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0C what would be the volume of this dry gas at STP

Dahasolnce [82]

The volume of the dry gas at stp is calculated as follows

calculate the number on moles by use of PV =nRT where n is the number of moles

n is therefore = Pv/RT
P = 0.930 atm
R(gas contant= 0.0821 L.atm/k.mol
V= 93ml to liters = 93/1000= 0.093L
T= 10 + 273.15 = 283.15k

n= (0.930 x0.093) /(0.0821 x283.15) = 3. 72 x10^-3 moles

At STp 1 mole = 22.4L
what about 3.72 x10^-3 moles

by cross multiplication

volume = (3.72 x10^-3)mole x 22.4L/ 1 moles = 0.083 L or 83.3 Ml

3 0

3 years ago