Answer:
Jordan has more green paints
Explanation:
Given
![Green = \frac{5}{8}](https://tex.z-dn.net/?f=Green%20%3D%20%5Cfrac%7B5%7D%7B8%7D)
![Blue = \frac{3}{6}](https://tex.z-dn.net/?f=Blue%20%3D%20%5Cfrac%7B3%7D%7B6%7D)
Required
Which paint does he have more?
For better understanding, it's better to convert both measurements to decimal.
For the green paint:
![Green = \frac{5}{8}](https://tex.z-dn.net/?f=Green%20%3D%20%5Cfrac%7B5%7D%7B8%7D)
![Green = 0.625](https://tex.z-dn.net/?f=Green%20%3D%200.625)
For the blue paint:
![Blue = \frac{3}{6}](https://tex.z-dn.net/?f=Blue%20%3D%20%5Cfrac%7B3%7D%7B6%7D)
![Blue = 0.5](https://tex.z-dn.net/?f=Blue%20%3D%200.5)
By comparison:
![0.625 > 0.5](https://tex.z-dn.net/?f=0.625%20%3E%200.5)
<em>This means that Jordan has more green paints</em>
Answer:
(d) a and c are correct
Explanation:
METALS : Metal are those materials which has very high ductility, high modulus of elasticity, good thermal and electrical conductivity
for example : iron, gold ,silver, copper
ALLOYS: Alloys are those materials which are made up of combining of two or more than two metals these also have good thermal and electrical conductivity and me liable property
for example ; bronze and brass
so from above discussion it is clear that option (d) will be the correct option
Technician B is right say that hard water potting i usually jut a Surface problem that can be wahed off.
What do you mean by Hard water?
The amount of dissolved calcium and magnesium in the water determines its hardness. Calcium and magnesium are the main dissolved minerals in hard water. The last time you washed your hands, you might have actually felt the effects of hard water.
What do you mean by acid rain?
Any type of precipitation that contains acidic elements, such as sulfuric or nitric acid, that falls to the ground from the atmosphere in wet or dry forms is referred to as acid rain, also known as acid deposition. Rain, snow, fog, hail, and even acidic dust can fall under this category.
Some plants are sensitive to excessive moisture around their root zone, so it may be necessary to increase drainage when growing plants in pots. Additionally, standing water at the bottom of the pot can cause root rot.
Many university agriculture extension agencies have thoroughly debunked the old garden myth that adding rocks to the bottom of a pot will increase drainage.
Learn more about hard water click here:
brainly.com/question/28178305
#SPJ4
Answer:
Explanation:
From the given question:
Using the distortion energy theory to determine the factors of safety FOS can be expressed by the relation:
![\dfrac{Syt}{FOS}= \sqrt{ \sigma x^2+\sigma y^2-\sigma x \sigma y+3 \tau_{xy^2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BSyt%7D%7BFOS%7D%3D%20%5Csqrt%7B%20%5Csigma%20x%5E2%2B%5Csigma%20%20y%5E2-%5Csigma%20x%20%5Csigma%20y%2B3%20%5Ctau_%7Bxy%5E2%7D%7D)
where; syt = strength in tension and compression = 350 MPa
The maximum shear stress theory can be expressed as:
![\tau_{max} = \dfrac{Syt}{2FOS}](https://tex.z-dn.net/?f=%5Ctau_%7Bmax%7D%20%3D%20%5Cdfrac%7BSyt%7D%7B2FOS%7D)
where;
![\tau_{max} =\sqrt{ (\dfrac{\sigma x-\sigma y}{2})^2+ \tau _{xy^2](https://tex.z-dn.net/?f=%5Ctau_%7Bmax%7D%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B%5Csigma%20x-%5Csigma%20%20y%7D%7B2%7D%29%5E2%2B%20%5Ctau%20_%7Bxy%5E2)
a. Using distortion - energy theory formula:
![\dfrac{350}{FOS}= \sqrt{94^2+0^2-94*0+3 (-75)^2}}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B94%5E2%2B0%5E2-94%2A0%2B3%20%28-75%29%5E2%7D%7D)
![\dfrac{350}{FOS}=160.35](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D160.35)
![{FOS}=\dfrac{350}{160.35}](https://tex.z-dn.net/?f=%7BFOS%7D%3D%5Cdfrac%7B350%7D%7B160.35%7D)
FOS = 2.183
USing the maximum-shear stress theory;
![\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{94-0}{2})^2+ (-75)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B94-0%7D%7B2%7D%29%5E2%2B%20%28-75%29%5E2)
![\dfrac{350}{2 FOS} =88.51](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D88.51)
![\dfrac{350}{ FOS} =2 \times 88.51](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B%20FOS%7D%20%20%3D2%20%5Ctimes%2088.51)
![{ FOS} =\dfrac{350}{2 \times 88.51}](https://tex.z-dn.net/?f=%7B%20FOS%7D%20%20%3D%5Cdfrac%7B350%7D%7B2%20%5Ctimes%2088.51%7D)
FOS = 1.977
b. σx = 110 MPa, σy = 100 MPa
Using distortion - energy theory formula:
![\dfrac{350}{FOS}= \sqrt{ 110^2+100^2-110*100+3(0)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%20110%5E2%2B100%5E2-110%2A100%2B3%280%29%5E2%7D)
![\dfrac{350}{FOS}= \sqrt{ 12100+10000-11000](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%2012100%2B10000-11000)
![\dfrac{350}{FOS}=105.3565](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D105.3565)
![FOS=\dfrac{350}{105.3565}](https://tex.z-dn.net/?f=FOS%3D%5Cdfrac%7B350%7D%7B105.3565%7D)
FOS =3.322
USing the maximum-shear stress theory;
![\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{110-100}{2})^2+ (0)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B110-100%7D%7B2%7D%29%5E2%2B%20%280%29%5E2)
![\dfrac{350}{2 FOS} ={ (\dfrac{110-100}{2})^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%7B%20%28%5Cdfrac%7B110-100%7D%7B2%7D%29%5E2)
![\dfrac{350}{2 FOS} =25](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D25)
FOS = 350/2×25
FOS = 350/50
FOS = 70
c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa
Using distortion- energy theory formula:
![\dfrac{350}{FOS}= \sqrt{ 90^2+20^2-90*20+3(-20)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%2090%5E2%2B20%5E2-90%2A20%2B3%28-20%29%5E2%7D)
![\dfrac{350}{FOS}= \sqrt{ 8100+400-1800+1200}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%208100%2B400-1800%2B1200%7D)
![\dfrac{350}{FOS}= 88.88](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%2088.88)
FOS = 350/88.88
FOS = 3.939
USing the maximum-shear stress theory;
![\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{90-20}{2})^2+ (-20)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B90-20%7D%7B2%7D%29%5E2%2B%20%28-20%29%5E2)
![\dfrac{350}{2 FOS} =\sqrt{ (35)^2+ (-20)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%2835%29%5E2%2B%20%28-20%29%5E2)
![\dfrac{350}{2 FOS} =\sqrt{ 1225+ 400](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%201225%2B%20400)
![\dfrac{350}{2 FOS} =40.31](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D40.31)
![FOS} =\dfrac{350}{2*40.31}](https://tex.z-dn.net/?f=FOS%7D%20%20%3D%5Cdfrac%7B350%7D%7B2%2A40.31%7D)
FOS = 4.341
Answer:
<h2>it's damage kindly be careful</h2>