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3 years ago

What is the difference between a refrigeration cycle and a heat pump cycle?

Engineering

1 answer:

sukhopar [10]3 years ago

5 0

Answer:

In refrigeration cycle heat transfer from inside refrigeration

In heat pump cycle heat transfer from environment

Explanation:

heat cycle is mechanical process use for cool the temperature but

In refrigeration heat transfer from inside of refrigeration that decrease temperature of refrigerator and in heat pump it decrease temperature negligible as compare to refrigerator

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Liquid water enters a valve at 300 kPa and exits at 275 kPa. As water flows through the valve, the change in its temperature, st

Elan Coil [88]

Answer:

The change in kinetic energy per unit mass of water flowing through the valve is - ΔKE = 0.025 KJ/Kg

Explanation:

Knowing

-Fluid is air

-inlet 1: P1 = 300 kPa

-exit 2: P2 = 275 kPa

density - rho= 1000 kg/m3

Using the formula

Δh = cΔT + Δp/rho

as change in temperature is neglected then change in enthalpy becomes

Δh = Δp/rho

energy equation could be defined by

Q - W = m(out) [h(out) $V^{2}$ (out)/2 + g Z(out)] - m(in) [h(in) $V^{2}$ (in)/2 + g Z(in)]

Q - W = m2 [h2 $V^{2}$ 2/2 + g Z2] - m1 [h1 $V^{2}$ 1/2 + g Z1]

as for neglecting potential energy effects

Q - W = m2(h2) - m1(h1)

as the system is adiabatic and has no work done

0 = m2 [h2 $V^{2}$ 2/2] - m1 [h1 $V^{2}$ 1/2]

from mass balance m1 = m2

0 = [h2 $V^{2}$ 2/2] - [h1 $V^{2}$ 1/2]

Change in kinetic energy could be defined by

ΔKE = $V^{2}$ 2/2 - $V^{2}$ 1/2

Change in specific enthalpy could be defined by

Δh = h2 - h1

Then the change in kinetic energy per unit mass of water flowing through the valve could be calculated as following

ΔKE = -Δh = ΔP/rho

-(275 - 300)/1000 = 0.025 KJ/Kg

- ΔKE = 0.025 KJ/Kg

3 0

4 years ago

Which words is used for actual result for a bug on a touch screen device

madam [21]

Glitch, error, system error, failed, sussy amogus :o

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3 years ago

Ferroconcrete is reinforced concrete that combines concrete and ________. A. Lead c. Copper b. Iron d. Aluminum.

Sveta_85 [38]

Answer:

b. Iron

Explanation:

6 0

3 years ago

What components should you inspect if the crankshaft end play is out of specifications?

xenn [34]

Answer:

gdyc ddxtfvytg4dgtfxdwcftcd3rcby

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4 years ago

A displacement field in the +ve x direction is given as u=3x^2+14y^2-8xy. Determine the strains in the x and y directions.

Misha Larkins [42]

Answer:

Given

$u_{x}(x,y)=3x^{2}+14y^{2}-8xy$

The normal strain in x -direction is defined as

$\epsilon _{xx}=\frac{\partial u_{x}}{\partial x}=\frac{\partial }{\partial x}(3x^{2}+14y^{2}-8xy)\\\\\therefore \epsilon _{xx}=6x-8y$

Similarly the normal strain in y-direction is defined as

$\epsilon _{yy}=\frac{\partial u_{y}}{\partial y}$

Now since there is no displacement field along y direction thus we have

$\epsilon _{yy}=0$

Similarly shear strain in xy plane is given by

$\epsilon _{xy}=\frac{1}{2}(\frac{\partial u_{x}}{\partial y}+\frac{\partial u_{y}}{\partial x})\\\\\therefore \epsilon _{xy}=\frac{1}{2}(\frac{\partial }{\partial y}(3x^{2}+14y^{2}-8xy)+\frac{\partial 0}{\partial x})\\\\\epsilon _{xy}=\frac{1}{2}(28y-8x)$

3 0

4 years ago