Answer:
peak-hour volume = 1890 veh/h
Explanation:
<u>Determine the peak-hour Volume </u>
Applying the equation below
Vp = v / ( PHF * N * Fg * Fdp ) -------------- ( 1 )
where :
Vp = 1250
v ( peak - hour volume ) = ?
PHF ( peak hour factor ) = 0.84
N = 2 lanes per direction
Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1
Fdp = 0.90
<u>Back to equation 1 </u>
v = Vp ( PHF * N * Fg * Fdp )
= 1250 ( 0.84 * 2 * 1 * 0.90 )
= 1890 veh/h
Answer:
To four significant digits = 2097 psi
Explanation:
<u>Applying the rule of thumb </u>
σ = Mc/I ---- ( 1 )
M = 1835 Ibf in , I/c = 0.875 in^3
∴ c/l = 1 / 0.875 = 1.1429
back to equation 1
σ = 1835 * 1.1429 = 2097.2215 psi
To four significant digits = 2097 psi
Answer:
with words giving information about the road ahead.
Explanation:
Answer: ok the best one would be letter s because it goes
Explanation:
467,,mm tubing should do
