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Nikolay [14]
3 years ago
10

Tony works as a Sorter in a processing factory. Which qualifications does he most likely have?

Engineering
2 answers:
svp [43]3 years ago
7 0

Answer:

answer is B

Explanation:

Vlada [557]3 years ago
4 0

Answer:

its b

Explanation:

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Air-conditioning principles are being discussed. Technician A states that heat always
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Describe the risks associated with their working environment (such as the tools, materials and equipment that they use, spillage
Llana [10]

The risks which are associated with such working environment and not reporting accidental breakages of tools is pollution and damage to the body system of individuals.

<h3>What is Risk?</h3>

This is defined as the possibility of something causing a bad event to occur and is common in workplace when tools are left carelessly which can cause injuries etc.

In the case of a working environment with oil spills, it can lead to slipping of the individuals present in the area and not reporting accidental breakages of tools or equipment could also lead to pollution and different forms of accident which thereby making it the most appropriate choice in this context.

Read more about Risk here brainly.com/question/1224221

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3 0
2 years ago
What are the main differences between structured,<br> O-O, and agile development methods?
fgiga [73]

Answer:While structured analysis sees procedures and information as isolated segments, object-oriented (O-O) analysis joins information and the procedures that follow up on the information into things called objects. O-O analysis utilizes protest models to show information, conduct, and by what implies objects influence different articles. By portraying the items (information) and techniques (forms) expected to help a business task, a framework engineer can outline reusable segments for quicker framework usage and diminished advancement cost.Numerous experts trust that, contrasted and organized examination, O-O strategies are more adaptable, effective, and reasonable in the present unique business environment. Agile improvement techniques have pulled in a wide after and a whole network of clients.

Agile  strategies ordinarily utilize a winding model, which speaks to a progression of cycles, or revisions,which depend on client criticism. Advocates of the winding model trust that this approach lessens dangers and accelerates programming advancement. Investigators ought to perceive that lithe techniques have points of interest and hindrances. By their tendency, dexterous strategies enable designers to be considerably more adaptable and responsive, however can be less secure than more customary techniques.For instance, without a point by point set of framework necessities, certain highlights asked for by a few clients won't not be predictable with the organization's bigger course of action. Other potential disservices of versatile strategies can incorporate feeble documentation, obscured lines of responsibility, and too little accentuation on the bigger business picture. Additionally, except if legitimately executed, a long arrangement of emphases may really add to extend cost and advancement time.

4 0
3 years ago
A diesel engine with CR= 20 has inlet at 520R, a maximum pressure of 920 psia and maximum temperature of 3200 R. With cold air p
Stella [2.4K]

Answer:

Cut-off ratio\dfrac{V_3}{V_2}=6.15

Cxpansion ratio\dfrac{V_4}{V_3}=3.25

The exhaust temperatureT_4=1997.5R

Explanation:

Compression ratio CR(r)=20

\dfrac{V_1}{V_2}=20

P_2=P_3=920 psia

T_1=520 R ,T_{max}=T_3,T_3=3200 R

We know that for air γ=1.4

If we assume that in diesel engine all process is adiabatic then

\dfrac{T_2}{T_1}=r^{\gamma -1}

\dfrac{T_2}{520}=20^{1.4 -1}

T_2=1723.28R

\dfrac{V_3}{V_2}=\dfrac{T_3}{T_2}

\dfrac{V_3}{V_2}=\dfrac{3200}{520}

So cut-off ratio\dfrac{V_3}{V_2}=6.15

\dfrac{V_1}{V_2}=\dfrac{V_4}{V_3}\times\dfrac{V_3}{V_2}

Now putting the values in above equation

\dfrac20=\dfrac{V_4}{V_3}\times 6.15

\dfrac{V_4}{V_3}=3.25

So expansion ratio\dfrac{V_4}{V_3}=3.25.

\dfrac{T_4}{T_3}=(expansion\ ratio)^{\gamma -1}

\dfrac{T_3}{T_4}=(3.25)^{1.4 -1}

T_4=1997.5R

So the exhaust temperatureT_4=1997.5R

3 0
4 years ago
Two balanced Y-connected loads in parallel, one drawing 15kW at 0.6 power factor lagging and the other drawing 10kVA at 0.8 powe
NemiM [27]

Answer:

(a) attached below

(b) pf_{C}=0.85 lagging

(c) I_{C} =32.37 A

(d) X_{C} =49.37 Ω

(e) I_{cap} =9.72 A and I_{line} =27.66 A

Explanation:

Given data:

P_{1}=15 kW

S_{2} =10 kVA

pf_{1} =0.6 lagging

pf_{2}=0.8 leading

V=480 Volts

(a) Draw the power triangle for each load and for the combined load.

\alpha_{1}=cos^{-1} (0.6)=53.13°

\alpha_{2}=cos^{-1} (0.8)=36.86°

S_{1}=P_{1} /pf_{1} =15/0.6=25 kVA

Q_{1}=P_{1} tan(\alpha_{1} )=15*tan(53.13)=19.99 ≅ 20kVAR

P_{2} =S_{2}*pf_{2} =10*0.8=8 kW

Q_{2} =P_{2} tan(\alpha_{2} )=8*tan(-36.86)=-5.99 ≅ -6 kVAR

The negative sign means that the load 2 is providing reactive power rather than consuming  

Then the combined load will be

P_{c} =P_{1} +P_{2} =15+8=23 kW

Q_{c} =Q_{1} +Q_{2} =20-6=14 kVAR

(b) Determine the power factor of the combined load and state whether lagging or leading.

S_{c} =P_{c} +jQ_{c} =23+14j

or in the polar form

S_{c} =26.92°

pf_{C}=cos(31.32) =0.85 lagging

The relationship between Apparent power S and Current I is

S=VI^{*}

Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.

(c) Determine the magnitude of the line current from the source.

Current of the combined load can be found by

I_{C} =S_{C}/\sqrt{3}*V

I_{C} =26.92*10^3/\sqrt{3}*480=32.37 A

(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω

Q_{C} =3*V^2/X_{C}

X_{C} =3*V^2/Q_{C}

X_{C} =3*(480)^2/14*10^3 Ω

(e) Compute the magnitude of the current in each capacitor and the line current from the source.

Current flowing in the capacitor is  

I_{cap} =V/X_{C} =480/49.37=9.72 A

Line current flowing from the source is

I_{line} =P_{C} /3*V=23*10^3/3*480=27.66 A

8 0
3 years ago
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