Answer: 9.09 %
Explanation:
To calculate the percentage concentration by volume, we use the formula:
Volume of ethanol (solute) = 30 ml
Volume of water (solvent) = 300 ml
Volume of solution= volume of solute + volume of solution = 30+ 300 = 330 ml
Putting values in above equation, we get:
Hence, the volume percent of solution will be 9.09 %.
By increasing the action energy
Answer:
part 1
3) 5.47 molecules
4) 11.15 moles
5) 2.95 × 10^23 molecules
6) 7670.9g
part2
1) 216000g
2) 5.71 molecules
3) 0.18 moles
4) 737.40g
5) 2.89×10^23 molecules
Explanation:
part 1
3) number of moles = (6.02 × 10^23)/11.0
=5.47molecules.
4) moles= (6.02 × 10^23)/(5.40×10^23)
= 11.15 moles
5) molar mass of NH3= 14+(3×1)= 14+3=17
number of molecules= (6.02 × 10^23) × 17/35
= (6.02 × 10^23)× 0.49 =2.95 × 10^23 molecules
6) molar mass of N2I6= (2×14) + (6×127)
= 28+762= 790g/mol
mass= 790 × (6.02 × 10^23)/(6.20×10^22)
=790× 9.71= 7670.9g
part 2
1) molar mass of CuBr= 64+80= 144g/mol
mass= 1500 × 144= 216000g
2) molecules = (6.02 × 10^23)/1.055
= 5.71 molecules
3) moles = (6.02 × 10^23)/(3.35×10^24)
= 0.18 moles
4) molar mass of SiO2= 28+ (2×16)= 28+32
=60gmol
mass= 60 × (6.02 × 10^23)/(4.90×10^22)
= 60× 12.29= 737.40g
5) molar mass of CH4= 12+(4×1)= 12+4=16g/mol
number of molecules= (6.02 × 10^23) × 16/33.6
= (6.02 × 10^23)× 0.48
= 2.89×10^23 molecules
Specific heat is the amount of heat absorb or released by a substance to change the temperature to one degree Celsius. To determine the specific heat, we use the expression for the heat absorbed by the system. Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:
Heat = mC(T2-T1)
By substituting the given values, we can calculate for C which is the specific heat of the material.
2510 J = .158 kg ( 1000 g / 1 kg) (C) ( 61.0 - 32.0 °C)
C = 0.5478 J / g °C
Answer:
Both weak interaction and strong interaction act only between non-atomic particles.
Explanation:
Arrange the four fundamental forces in increasing strength:
- Gravity,
- "Weak" interaction,
- Electromagnetic interaction, and
- Strong interaction.
Thus, this question is about the strong and weak interactions. In particular, the choices are concerned about properties common to both types of interactions.
- The ranges of electromagnetic interaction and gravity are infinite. However, the ranges of strong and weak interactions are much smaller. The maximum range of weak interactions is around
. The maximum range of strong interactions is around 
.
- Weak interaction occurs between left-hand fermions. This class of particles includes neutrinos, which do not carry any charge. The most energetic strong interactions occur between quarks, which are all charged. Some of the weaker residual strong interactions occur between particles that are made of quarks. That includes both protons and neutrons (which do not carry any charge.) This type of strong interaction holds nuclei intact.
Consider the choices:
- The range of neither weak nor strong interactions is infinite. This range is smaller than the radius of atomic nuclei.
- Strong and weak interactions indeed act between charged particles. However, there are exceptions such as neutrinos and neutrons.
- The ranges of strong and weak interactions are so small that they are nearly undetectable outside of atomic nuclei. Both interactions act only between non-atomic particles such as protons and neutrons as well as electrons and quarks.
- Atoms are too large to experience weak and strong interactions.
