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2 years ago

Why are girls so confusing

Physics

2 answers:

ohaa [14]2 years ago

8 0

Right? i’m a girl and i think we’re confusing
we’re especially confusing when it comes to liking boys

liubo4ka [24]2 years ago

8 0

We’re just complex and fricking bleed out every month for a week but still forced to do normal stuff like pe o stg the blood will go everywhere

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What are various names of tropical storms<br> based upon the ocean they occur in?

SpyIntel [72]

Answer:

hurricanes,Typhoons and cyclones

4 0

2 years ago

A compound consisting of only phosphorous and oxygen atoms is 43.64 % phosphorus by mass.The molecular mass/formula weight of th

DanielleElmas [232]

First, we calculate the mass of Phosphorous present:
283.88 x 0.4364
= 123.88 amu
Atomic mass of P is 31 amu

moles of P = mass / Ar
= 123.88 / 31
= 4.0 moles

We know that one mole of substance has 6.02 x 10²³ particles
Atoms of P = 4 x 6.02 x 10²³
= 2.41 x 10²⁴ atoms

6 0

3 years ago

Astronauts brought back 500 lb of rock samples from the moon. how many kilograms did they bring back? 1 kg = 2.20 lb 227 kg 227

Aleksandr [31]

Astronauts brought back 227kg of rock samples from the moon.

<h3>Who is an astronaut?</h3>

A person who has been trained, outfitted, and sent into space by a human spaceflight program to serve as a commander or crew member is known as an astronaut (from the Ancient Greek words (astron), meaning "star," and (nautes), meaning "sailor"). The word is occasionally used to refer to anyone who flies into space, including scientists, politicians, journalists, and tourists, despite the fact that it is typically only designated for professional space travelers.

600 astronauts have made space flights since 1961. Up until 2002, only governments—either the military or civilian space agencies—sponsored and educated astronauts. A new class of astronaut was introduced in 2004 with the suborbital flight of the privately funded SpaceShipOne: the commercial astronaut.

Explanation:

1kg=2.20lb

500lb=(1/2.20*500)kg

500lb=227kg

To learn more about astronaut , visit:

brainly.com/question/11244838

#SPJ4

7 0

1 year ago

Un objeto se suelta desde determinada altura y emplea un tiempo t en caer al suelo. Si se cuadruplica la altura desde la cual se

blondinia [14]

When an object falls from a h height, you should work with the uniformly accelerated linear movement equations:

y=½*a*t²+Vo*t+yo

You should consider:

a=-g=-10m/s²

yo=h

If it’s a freefall, it means it starts from rest, which means it has no initial velocity:

Vo=0

Replacing that information in the equation:

y=½*(-10m/s²)*t²+0*t+h=-5m/s²*t²+0+h=-5m/s²*t²+h

So this is the

Besides, if you want to find out how long it takes for it to get to the floor, you should put the height of the floor as final height, which would be 0 (assuming the initial height has been measured from there):

y=0

0=-5m/s²*t²+h

5m/s²*t²=h

t²=h/(5m/s²)

t=√(h/(5m/s²))

t=√(hs²/(5m))

t=(√(h/(5m)))s

<span>If we <span>quadruple </span>h:</span>

t2=(√(h2/(5m)))s=(√(4*h1/(5m)))s=(√4)*(√h1/(5m)))s=2*(√h1/(5m)))s=2*t1

This 4 goes inside the square root, so then it converts to 2. So the new time is twice as much the previous time.

Concerning velocity, you have to use the other equation:

v=at+vo

As I said before, a is gravity and vo is zero.

v=-10m/s²*t+0=-10m/s²*t

Final velocity is directly related to time, so if time is doubled, so is velocity.

v2=-10m/s²*t2=-10m/s²*(2*t1)=2*(-10m/s²*t1)=2*v1

<span>So the correct answer is A, and the other ones are false.</span>

8 0

3 years ago

A rock falls from rest off a cliff and hits the ground in 2 seconds. If there is no air resistance, determine the rock's velocit

mihalych1998 [28]

Answer:

19.6m/s

Explanation:

A Rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for certain period of time, for such motion following equation of motion can be used.

$v(t) = v_{0} +at$

here in our case $v_{0} =0$ because object starts off from rest and $a = g =9.8m/s^2$ is acceleration because of gravity ( Motion under gravity).

and of course t = 2 second.

Now by substituting all this information in equation of motion we get.

$v(2s) = 0+9.8m/s^2 *2s = 19.6m/s$

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.

A rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for a certain period of time, for such motion following equation of motion can be used.

here in our case because object starts off from rest and is acceleration because of gravity ( Motion under gravity).

and of course t = 2 seconds.

Now by substituting all this information in equation of motion we get.

V = 19.6m/s

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.

5 0

3 years ago