Answer:
Graphs are pictorial representations of relationships.
We have that the speed of the ice at the bottom is mathematically given as
v=1.8812m/s
<h3>The speed of the ice at the bottom </h3>
Question Parameters:
A 8.00 kg block of ice, released from rest
at the top of a 1.50-m-long frictionless ramp,
slides downhill, reaching a speed of 2.70 m/s
constant friction force of 10.0 N parallel to the surface of the ramp
Generally the equation for the Potential Energy is is mathematically given as
P.E=K.E+W_{fric}
Therefore
mgh=0.5mv^2+W_{fric}
Where
W_{fric}=F.S
W_{fric}=10*1.50
W_{fric}=15
And
mgh=0.5mv^2+
h=0.3719
Hence
0.5(8.00)(v^2)=(8.00)(9.8)(0.3719)-15
v^2=3.53924
v=1.8812m/s
For more information on Velocity visit
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Answer:
light in the UV range.
Explanation:
Noble gases and halogens can combine to form lasers called Excimer, for this to happen the noble gas must be ionized with a high voltage discharge, thus forming a molecule of the type
noble gas (X) + halogen (H) → XH
This molecule is highly unstable and decomposes within a few nanoseconds, emitting light in the UV range.
Answer:
La intensidad del campo eléctrico es 70312.5
.
Explanation:
La perturbación que crea en torno a ella una carga eléctrica se representa mediante un vector denominado campo eléctrico.
Se dice que un campo eléctrico es uniforme en una región del espacio cuando la intensidad de dicho campo eléctrico es el mismo en todos los puntos de dicha región.
El campo eléctrico E creado por la carga puntual q en un punto cualquiera P se define como:
![E=k*\frac{q}{r^{2} }](https://tex.z-dn.net/?f=E%3Dk%2A%5Cfrac%7Bq%7D%7Br%5E%7B2%7D%20%7D)
donde q es la carga creadora del campo, k es la constante electrostática y r es la distancia desde la carga fuente al punto P.
En este caso, los datos son:
- k= 9*10⁹
![\frac{N*m^{2} }{C^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BN%2Am%5E%7B2%7D%20%7D%7BC%5E%7B2%7D%20%7D)
- q= 5*10⁻⁶ C
- r= 0.8 m
Reemplazando:
![E=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{5*10^{-6} C}{(0.8 m)^{2} }](https://tex.z-dn.net/?f=E%3D9%2A10%5E%7B9%7D%5Cfrac%7BN%2Am%5E%7B2%7D%20%7D%7BC%5E%7B2%7D%20%7D%20%20%2A%5Cfrac%7B5%2A10%5E%7B-6%7D%20C%7D%7B%280.8%20m%29%5E%7B2%7D%20%7D)
Resolviendo:
E= 70312.5 ![\frac{N}{C}](https://tex.z-dn.net/?f=%5Cfrac%7BN%7D%7BC%7D)
<em><u>La intensidad del campo eléctrico es 70312.5 </u></em>
<em><u>.</u></em>
It is proved that at every point on an equipotential surface, the surface must be perpendicular to the electric field.
<h3>What is meant by equipotential surface?</h3>
- An equipotential surface is any surface where the potential is constant. In other words, any two points on an equipotential surface have the same potential difference.
- Equipotential surfaces have the following important properties: 1. The work done in moving a charge across an equipotential surface is equal to zero.
- An equipotential surface is one on which all of the points on it have the same electric potential.
- This means that a charge has the same potential energy at all points along the equipotential surface.
- We have to prove that at every point on an equipotential surface, the surface must be perpendicular to the electric field.
The potential between two points (A) and (B) on an equipotential surface is given by:
W AB = q ΔV = -q
E dS
By the definition ΔV at an equipotential surface is zero.
-q
E dS = 0
E dS = 0
ES cos θ = 0
Therefore, cos θ <em> must be 0°</em> or 90° for a field to be non electric.
Hence, it is proved that at every point on an equipotential surface, the surface must be perpendicular to the electric field.
To learn more about equipotential surfaces, refer to:
brainly.com/question/14675095
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