Question

An object in static equilibrium has a coefficient of static friction as 0.110. If the normal force acting on the object is 95.0 newtons, what is the mass of the object? 9.60 kilograms 10.5 kilograms 85.3 kilograms 95.0 kilograms 1.00 × 102 kilograms

Answer 1

Answer : The mass of the object is, 86.3 kilograms

Solution :

The equation used for static friction is,

$F_s=\mu_s\times N\\\\F_s=\mu_s\times (m\times g)$

where,

$F_s$ = force of static friction = 95 N

$\mu_s$ = coefficient of static friction = 0.110

N = normal force

m = mass of the object

g = gravity on earth = $10m/s^2$

Now put all the given values in the above equation, we get the mass of the object.

$F_s=\mu_s\times (m\times g)$

$95N=(0.110)\times (m\times 10m/s^2)$

$m=86.3Kg$

Therefore, the mass of the object is, 86.3 kilograms

Answer 2

m = n/g = 95/9.8 = 9.69 kg

Hope this helps.