Answer:
85.5 km/h
Explanation:
= time interval for first phase = 14 min =
h = 0.233 h
= time interval for second phase = 46 min =
h = 0.767 h
= average speed for the entire trip = 74 km/h
= average speed in first phase = 36 km/h
= average speed in second phase
= distance traveled in first phase
= distance traveled in first phase
average speed is given as




km/h
The answer to this is Protostar.
This is a process where it is gathering mass from its parent molecular cloud. Its a very young star meaning, the star was now born.
Hope this helped :)
Have a great day
When acceleration is constant, the average velocity is given by

where
and
are the final and initial velocities, respectively. By definition, we also have that the average velocity is given by

where
are the final/initial displacements, and
are the final/initial times, respectively.
Take the car's starting position to be at
. Then

So we have

You also could have first found the acceleration using the equation

then solve for
via

but that would have involved a bit more work, and it turns out we didn't need to know the precise value of
anyway.