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KatRina [158]
3 years ago
6

China's GDP passed one trillion USD between Between 2005 and 2010, China's GDP increased by approximately

Physics
2 answers:
Ede4ka [16]3 years ago
5 0

Answer:

1995 and 2000.4 trillion

Explanation:

Edge 2021

maksim [4K]3 years ago
3 0

Answer:

1995 and 2000 , 4 trillions

Explanation:

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The answer here could be pressure vs. temperature.

Think of PV=nRT. T is related to P the same way as n is (assuming all other variables are kept constant).
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A lowly high diver pushes off horizontally with a speed of 2.00 m/s from the platform edge 10.0 m above the surface of the water
VladimirAG [237]

Answer:

(a) 1.6m

(b) 6.86m

(c) 2.86s

Explanation:

This is a horizontal shooting problem, so we will use the following equations.

For horizontal distance x we use:

x(t)=x_{0}+v_{0}t

Where x(t) is the horizontal distance at a time t, x_{0} is the initial horizontal position which in this case will be zero: x_{0}=0. And v_{0} is the initial speed: v_{0}=2m/s

So to solve (a):

(a) At what horizontal distance from the edge is the diver 0.800 s after pushing off?

we have that the time is: t=0.8s so the horizontal distance is:

x(0.8)=(2m/s)(0.8s)1.6m

<u>The answer for (a) is 1.6m</u>

Now, to solve (b) we need the equation for vertical distance:

y(t)=y_{0}-\frac{1}{2}gt^2

Where y(t) is the vertical distance at a time t, y_{0} is the initial vertical distance: y_{0}=10m And g is the gravitational acceleration: g=9.81m/s^2 }

(b) At what vertical distance above the surface of the water is the diver just then?

The time is the same as in the last question: t=0.8s

y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.8)^2

y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.64s^2)

y(0.8)=10m-\frac{1}{2}(6.2784m)

y(0.8)=10m-(3.1392)

y(0.8)=6.86m

<u>the answer to (b) is 6.86m</u>

(c) At what horizontal distance from the edge does the diver strike the water?

To solve (c) we first need to know how long it took to reach the height of the water, that is, for what time y = 0

Using y(t)=y_{0}-\frac{1}{2}gt^2

if y(t)=0

0=10-\frac{1}{2}gt^2\\-10=-\frac{1}{2}gt^2\\20=gt^2\\\frac{20}{g}=t^2\\ \sqrt{\frac{20}{g}}=t

and since g=9.81m/s^2

t=\sqrt{\frac{20}{9.81} } =\sqrt{2.039}=1.43s

At t=1.43s the car hits the water, so the horizontal distance at that time is:

x(t)=x_{0}+v_{0}t

x(1.43)=(2m/s)(1.43s)=2.86m

<u>the answer to (c) is 2.86s</u>

6 0
3 years ago
Someone help me! you get 27 points if you get it right
pashok25 [27]

Answer:

1. D

2. D

3. A

The reason why your body goes right and the car car goes left is because your body tries to stay where it was, which is on the right. Your upper body doesn't feel a force and because of that continues in the same direction. Your lower half is pulled out from under you by seat friction to the left, leaving you leaning to the right.

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For a given ideal gas if it temperature is constant the pressure of the gas is proportional ??
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Answer:

C) Inversely to its volume

Explanation:

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What does the velocity vs. time (v vs t) graph show?
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Answer:

the acceleration of a moving object

Explanation:

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