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Arlecino [84]
3 years ago
9

Help me pleaseeeeeeeeeeeeeeee

Chemistry
1 answer:
Burka [1]3 years ago
8 0

Answer:

C) 2-bromo-1-methylpropane

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What type of cryptography uses two keys instead of just one, generating both a private and a public key?
Alexxx [7]

Answer:

It is known as asymmetric key cryptography it is also called public key cryptography.

Explanation:

Asymmetric key cryptography method makes use of two keys.One is used for encryption and the second one for decryption. The public key serves to encrypt plain text or verify a digital signature, while the private key is used to decrypt or decipher the encrypted text or to create a digital signature.

3 0
3 years ago
How to make Sodium thiosulfate
Arada [10]

Explanation:

Method of prepration of sodium thiosulphate - definition

In the laboratory, this salt can be prepared by heating an aqueous solution of sodium sulphite with sulphur or by boiling aqueous NaOH and sulfur according to this equation:

6NaOH + 4 S _{2} Na _{2} S ->Na _{2} S_{2}O_{3}+ 3H _{2}O.

3 0
3 years ago
PLZZZZZZZ HELP MEEEEEE!!!!!!!!!!
nikitadnepr [17]

Answer:

Its Obviously Dinosaurs

Explanation: They died 65 million years ago

7 0
3 years ago
Why couple should use a method of birth control
Tresset [83]

Answer:

because it will control the birth of a child which can happen alot being overpopulated in the country or world. It also can mange their life and create a small and happy and healthy family.Also the child can get more love and support from their parents if they have less children and it wont be a taruma for the couple as well.  because growing a child can be expensive time costly and really hard.

Explanation:

plz mark me as a brainlest a and thanks my answer

3 0
3 years ago
Sodium thiosulfate, Na 2S 2O 3, is used as a "fixer" in black and white photography. Identify the reducing agent in the reaction
Tatiana [17]

Answer: Reducing agent in the given reaction is S_{2}O^{2-}_{3}.

Explanation:

A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.

In the given reaction, oxidation state of sulfur in S_{2}O^{2-}_{3} is +2 and I_{2}(aq) has 0 oxidation state.

In S_{4}O^{2-}_{6}(aq) oxidation state of S is 2.5 and in 2I^{-}(aq) oxidation state of I is -1.

Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.

Thus, we can conclude that reducing agent in the given reaction is S_{2}O^{2-}_{3}.

8 0
3 years ago
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