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drek231 [11]
3 years ago
15

Who first arranged the elements according to atomic mass ?

Chemistry
1 answer:
kondaur [170]3 years ago
6 0

Answer:

Dmitri Mendeleev

Explanation:

In 1869, just five years after John Newlands put forward his Law of Octaves, a Russian chemist called Dmitri Mendeleev published a periodic table. Mendeleev also arranged the elements known at the time in order of relative atomic mass, but he did some other things that made his table much more successful.

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Which way would CCI2F2 orient in an electric field?
ArbitrLikvidat [17]

Answer:

See explanation

Explanation:

In looking at molecules to determine whether they are polar or not we have to look at two things basically;

i) presence of polar bonds

ii) geometry of the molecule

Now, we know that CCI2F2 is a tetrahedral molecule, but the molecule is not symmetrical. It has four polar bonds that are not all the same hence the molecule is polar.

In an electric field, polar molecules orient themselves in such a way that  the positive ends of the molecule are being attracted to the negative plate while the negative ends of the molecules are attracted to the positive plate.

So the positive ends of CCI2F2  are oriented towards the negative plate of the field while the negative ends of CCI2F2 are oriented towards the positive ends of the field.

3 0
3 years ago
Nitrogen gas reacts with hydrogen gas to produce ammonia. How many liters of hydrogen gas at 95kPa and 15∘C are required to prod
viktelen [127]

Answer:

222.30 L

Explanation:

We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:

Mass of NH₃ = 100 g

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 100 / 17

Mole of NH₃ = 5.88 moles

Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e

Xmol of H₂ = (3 × 5.88)/2

Xmol of H₂ = 8.82 moles

Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:

Pressure (P) = 95 KPa

Temperature (T) = 15 °C = 15 + 273 = 288 K

Number of mole of H₂ (n) = 8.82 moles

Gas constant (R) = 8.314 KPa.L/Kmol

Volume (V) =?

PV = nRT

95 × V = 8.82 × 8.314 × 288

95 × V = 21118.89024

Divide both side by 95

V = 21118.89024 / 95

V = 222.30 L

Thus the volume of Hydrogen needed for the reaction is 222.30 L

8 0
3 years ago
Sterling silver is:
dexar [7]

Answer:

It’s D

Explanation:

It’s an alloy so it is not pure. If you take a small sample and analyze it, the mixture will be similar throughout. Think of Gatorade as a homogeneous mixture because it is the same concentration of all ingredients throughout. Think of pizza for heterogeneous mixtures. There isn’t the pepperoni (or whatever you prefer) throughout.

4 0
3 years ago
Metalloids/semiconductors are elements that...
Sonbull [250]

Answer:

I think its have properites of both metals and non metals

Explanation:

4 0
3 years ago
BaO2(s) + 2HCl(aq) → H2O2(aq) + BaCl2(aq) What mass of hydrogen peroxide should result when 1.50 g barium peroxide is treated wi
Solnce55 [7]

Answer:

mass H2O2 = 0.31g H2O2

mass unreacted = 0.0745g BaO2

Explanation:

Mw BaO2 = 169.33 g / mol

Mw HCl = 36.46 g/mol

Mw H2O2 = 34.0147 g/mol

LR:

⇒ mol BaO2 = 1.50g BaO2 * mol / 169.33 g = 8.86E-3 mol BaO2 / 1 = 8.86E-3 mol BaO2

⇒ mol HCl = 25.0 mL * 0.0272g / mL * mol / 36.46g = 0.0186 mol HCl / 2 = 9.3E-3 mol HCl.....L.R

mol H2O2:

⇒ 0.0186mol HCl * (mol H2O2 / 2mol HCl) = 9.325E-3 mol H2O2

⇒ g H2O2 = 9.325E-3mol H2O2 * 34.0147g H2O2 / mol H2O2 = 0.31g H2O2

mass of wich reagent is left unreacted:

mol that react BaO2 = 0.0186mol HCl * (mol BaO2 / 2mol HCl) = 9.3E-3mol BaO2

mol that unreacted BaO2 = 9.3E-3 - 8.86E-3 = 4.4E-4 mol BaO2

g unreacted BaO2 = 4.4E-4mol BaO2 * (169.33g BaO2 / mol BaO2) = 0.0745g BaO2

8 0
3 years ago
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