(a) The maximum height of the ball above the ground is 12.5 m and the time of motion is 1.43 s.
(b) The time taken for the ball to contact the other player at 0.5 m above the ground is 3.0 s.
<h3>Maximum height reached by the ball</h3>
The maximum height reached by the ball is calculated as follows.
At maximum height, the final velocity, v = 0
dh/dt = v = 0
dh/dt = -2(4.9)t + 14
0 = -9.8t + 14
9.8t = 14
t = 1.43 s
H(1.43) = -4.9(1.43)² + 14(1.43) + 2.5
H(1.43) = -10.02 + 20.02 + 2.5
H(1.43) = 12.5 m
<h3>Time to reach maximum height</h3>
12.5 = -4.9t² + 14t + 2.5
4.9t² - 14t + 10 = 0
t = 1.43 s
<h3>Time for the ball to reach 0.5 m above the ground</h3>
0.5 = -4.9t² + 14t + 2.5
4.9t² - 14t + - 2 = 0
t = 3.0 seconds
The complete question is below:
In a volleyball match Hanein serves the volleyball at 14 m/s, from a height of 2.5 m above the court. The height of the ball in flight is estimated using the equation, h = -4.9t² + 14t + 2.5, where t is the time in second and h is height above ground, in metres.
Learn more about time of motion here: brainly.com/question/2364404
#SPJ1
Answer:
x=25
x=47
y=25 x=10
y=20
Step-by-step explanation:
2x+10=60
-10 -10
2x=50
2x/2=50/2
x=25
2x+6=100
-6 -6
2x=94
2x/2=94/2
x=47
5y-25=100
+25 +25
5y=125
5y/5=125/5
y=25
11x-30+100=180
11x+70=180
-70 -70
11x=110
11x/11=110/11
x=10
7y-10=3y+70
+10 +10
7y=3y+80
-3y-3y
4y=80
4y/4=80/4
y=20
hopefully this helps :)
Cross multiply:-
3(b - 2) = (2b - 5)(b + 2)
3b - 6 = 2b^2 + 4b - 5b - 10
2b^2 - 4b - 4 = 0
b^2 - 2b - 2 = 0
b = 2.73, -0.73 Answer
