The subtraction of complex numbers 
is cos(π)+i sin(π).
Given 
[cos(3π/4+i sin(3π/4) and 
=cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which 
. It looks like a+ bi.
We have to first solve 
and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/+1/)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of 
,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
#SPJ4
Answer:
7/10 hours
Step-by-step explanation:
her first assignment took 1/2 hour
her second assignment took 1/5 hour
so in total she took 1/2 + 1/5
we need to find a common denominator
the lcm(2,5)=10
so multiply 1/2 by 5/5 to obtain 5/10
multiply 1/5 by 2/2 to obtain 2/10
5/10 + 2/10 = 7/10
Translate the words into math and solve for x. Any questions let me know.
9 times 2.75 equals 24.75
Answer:
3/2 or 1 1/2
Step-by-step explanation:
.
