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Vera_Pavlovna [14]
2 years ago
15

Which facts did you include in your response? Check all that apply.

Chemistry
2 answers:
pashok25 [27]2 years ago
7 0

Answer:

All Are correct responses

klasskru [66]2 years ago
5 0

Answer:

All options apply

Explanation:

Take for example the following oxidation-reduction reaction:

2 H2  + O2   -> 2 H2O  

Hydrogen is oxidized, then its oxidation number increased (from 0 to +1) and lost electrons.

On the other hand, oxygen is reduced,  that is, its oxidation number decreased (from 0 to -2) and gain the electrons lost by hydrogen.

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How to balance CH4 + O2=CO2+H2O
sertanlavr [38]

Answer:

LHS-RHS

1 C - 1 C

4 H-2 H

2 O- 3 O

So on right side 2 hydrogen are less and one oxygen is more..so

Balanced equation is

CH4+2O2==CO2 + 2H2O

Explanation:

7 0
3 years ago
Read 2 more answers
Can someone help me please
kvasek [131]

Answer:

D

Explanation:

John is not a very good businessman.

:D

6 0
3 years ago
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The ideal gas heat capacity of nitrogen varies with temperature. It is given by:
hammer [34]

Answer:

A)  1059 J/mol

B)  17,920 J/mol

Explanation:

Given that:

Cp = 29.42 - (2.170*10^-3 ) T + (0.0582*10^-5 ) T2 + (1.305*10^-8 ) T3 – (0.823*10^-11) T4

R (constant) = 8.314

We know that:

C_p=C_v+R

We can determine C_v from above if we make C_v the subject of the formula as:

C_v=C_p-R

C_V = 29.42-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4-8.314

C_V = 21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4

A).

The formula for calculating change in internal energy is given as:

dU=C_vdT

If we integrate above data into the equation; it implies that:

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4\,) du

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 1059J/mol

Hence, the internal energy that must be added to nitrogen in order to increase its temperature from 450 to 500 K = 1059 J/mol.

B).

If we repeat part A for an initial temperature of 273 K and final temperature of 1073 K.

then T = 273 K & T2 = 1073 K

∴

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})273/1+(5.82*10^{-7})1073/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 17,920 J/mol

3 0
3 years ago
Explain how to use a graph to show whether or not the speed of an object is constant.
Sonbull [250]

Answer:

A horizontal line on a speed-time graph represents a constant speed. A sloping line on a speed-time graph represents an acceleration. The sloping line shows that the speed of the object is changing. The object is either speeding up or slowing down.

3 0
3 years ago
How many grams of methionine (MW = 149.21) are needed to make 20 mL of a 150 mM solution?
Leni [432]

Answer:

0.45 g

Explanation:

Step 1: Given data

  • Molar mass of methionine (M): 149.21 g/mol
  • Volume of the solution (V): 20 mL
  • Concentration of the solution (C): 150 mM

Step 2: Calculate the moles of methionine (n)

We will use the following expression.

n = C × V

n = 150 × 10⁻³ mol/L × 20 × 10⁻³ L

n = 3.0 × 10⁻³ mol

Step 3: Calculate the mass of methionine (m)

We will use the following expression.

m = n × M

m = 3.0 × 10⁻³ mol × 149.21 g/mol

m = 0.45 g

7 0
3 years ago
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