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2 years ago

Which facts did you include in your response? Check all that apply.

Chemistry

2 answers:

pashok25 [27]2 years ago

7 0

Answer:

All Are correct responses

klasskru [66]2 years ago

5 0

Answer:

All options apply

Explanation:

Take for example the following oxidation-reduction reaction:

2 H2 + O2 -> 2 H2O

Hydrogen is oxidized, then its oxidation number increased (from 0 to +1) and lost electrons.

On the other hand, oxygen is reduced, that is, its oxidation number decreased (from 0 to -2) and gain the electrons lost by hydrogen.

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How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant

nika2105 [10]

<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

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Atomic Structure

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<h3>Explanation:</h3>

Step 1: Define

[Given] 0.456 g H₂O (water)

Step 2: Identify Conversions

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.025305 \ mol \ H_2O$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.025305 mol H₂O ≈ 0.0253 mol H₂O

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