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masya89 [10]
3 years ago
14

Mghso4.5h2O name and molar mass

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0
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Predictable moderate winds between 5 & 25 degrees North or South latitude are called?
Grace [21]

Answer:

احبـــــــــــــــــــك

لول ملل اقولج انا اسفه

6 0
3 years ago
Balance the following equation; then determine how many grams of CO2 will be produced when 40.0 mol of CO reacts with Fe2O3.
sashaice [31]

 Fe2O3      +       3CO -------->    2Fe    +      CO2

      1           :          3         :            2      :         3

   13.3       <---     40    ------> 26.6      --->     40    ( mol)

n = m/M

m CO2 = n.M = 13.3  .    40   =  532 ( g)

p/s : i hope that this will help  ( cause i'm not really good at english :}}} )

6 0
3 years ago
Gold has density of 19.3 g/cm3; how many grams of gold are in a 16.0 cm3 gold bar?
Andre45 [30]
To determine the mass of gold, we simply multiply the density and volume. Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We do as follows:

mass = density x volume
mass = 19.3 g/cm^3 ( 16.0 cm^3 )
mass = 308.8 g
6 0
3 years ago
What is not a way that a mineral can be formed
Yuri [45]
<span> under extreme heat or pressure
 crystallize from magma
 precipitate from a solution reaction of hot mixture with water and a dissolved substance</span>
8 0
3 years ago
What is the empirical formula of a compound that is composed of 60.94% carbon 15.36% hydrogen and 23.70% nitrogen
Musya8 [376]

Answer:

C₃H₉N

Explanation:

The empirical formula of a compound is the fundamental and basic possible formula that shows the mole ratio of the atoms of each element in a molecule of the compound.

mole ratio of carbon = 60.94/12 = 5.078

mole ratio of hydrogen = 15.36/1  = 15.36

mole ratio of nitrogen = 23.70/14 = 1.693

Now; we will divide by the smallest value

So; carbon = 5.078/1.693 = 2.99 ≅ 3.0

hydrogen = 15.36/1.693 = 9.07 ≅ 9.0

nitrogen = 1.693/1.693 = 1 ≅ 1

Thus,  the empirical formula is = C₃H₉N

6 0
3 years ago
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