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2 years ago

Gravitational forces is ------ force

Physics

1 answer:

mel-nik [20]2 years ago

7 0

Answer:

Gravitational force is <u>noncontact</u> force

Explanation:

Contact force occurs due to the contact between two different objects. Non-contact force occurs due to either attraction or repulsion between two objects such that there is no contact between these objects. There is no field linked with the contact force. ... Gravitational force is an example of a non-contact force.

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if the current is 0.4 A for the 20 ohm resistor, what is the value for the potential difference? ii) Would it be different for t

Genrish500 [490]

Answer:potential difference is more or less like voltage. Using ohms, V=IR

Where V is Voltage

I is Current =0.4A

R is Resistance=20ohms

V=0.4*20

V=8V

Hence the potential difference will be 8V.

ii) V=0.4*30

V=12V

Explanation:

The voltage of potential difference is directly proportional to the current and the resistance. So if one increase or decrease, it will have impact on the other.

From the calculations, when the resistance increase, the voltage will increase to appreciate the change.

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2 years ago

What happens to kinetic energy when you increase the mass?

Rus_ich [418]

Increasing mass increases kinetic energy. This can be seen in the equation KE = 1/2 (m) (v)^2

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2 years ago

The state of matter that has low thermal expansion

leonid [27]

Answer:

Matter

Explanation:

Because it is solid

6 0

2 years ago

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What what is the change in internal energy if 500 joule of heat is added to a system and 125 joule of work are done on a system

eduard

Answer:

DU = 375 Joules

Explanation:

Given the following data;

Quantity of heat = 500 Joules

Work done = 125 Joules

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

DU is the change in internal energy.
Q is the quantity of energy.
W is the work done.

Substituting into the formula, we have;

DU = 500 - 125

<em>DU = 375 Joules</em>

8 0

2 years ago

A 500 kg dragster accelerates from rest to a final speed of 100 m/s in 400 m (about a quarter of a mile) and encounters an avera

Fantom [35]

In order to accelerate the dragster at a speed $v_f = 100 m/s$ , its engine must do a work equal to the increase in kinetic energy of the dragster. Since it starts from rest, the initial kinetic energy is zero, so the work done by the engine to accelerate the dragster to 100 m/s is
$W= K_f - K_i = K_f = \frac{1}{2}mv_f^2=2.5 \cdot 10^6 J$

however, we must take into account also the fact that there is a frictional force doing work against the dragster, and the work done by the frictional force is:
$W_f = F_f d = -(1200 N)(400 m)= -4.8 \cdot 10^5 J$
and the sign is negative because the frictional force acts against the direction of motion of the dragster.

This means that the total work done by the dragster engine is equal to the work done to accelerate the dragster plus the energy lost because of the frictional force, which is $-W_f$ :
$W_t = W + (-W_f)=2.5 \cdot 10^6 J+4.8 \cdot 10^5 J=2.98 \cdot 10^6 J$

So, the power delivered by the engine is the total work divided by the time, t=7.30 s:
$P= \frac{W}{t}= \frac{2.98 \cdot 10^6 J}{7.30 s}=4.08 \cdot 10^6 W$

And since 1 horsepower is equal to 746 W, we can rewrite the power as
$P=4.08 \cdot 10^6 W \cdot \frac{1 hp}{746 W} =547 hp$

3 0

3 years ago

Read 2 more answers

Gravitational forces is ------ force​

Gravitational forces is ------ force