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2 years ago

6

at a major league baseball game, you are sitting a distance 52 meters from home plate. how much time passes between seeing josh

Hamilton hit a home run and actually hearing the crack of the bat?

1 answer:

brilliants [131]2 years ago

8 0

sound travels through air at around 340 - 350 m/s.

to cover 52 meters takes it, say, (52/345) = about 0.15 second

This would be the same time-lag even if it were not a major-league game,
except that you might not be able to get a seat 52 meters from home plate
at a little league or t-ball game.

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1 year ago

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An Atwood machine consists of two masses, mA = 6.8 kg and mB = 8.0 kg , connected by a cord that passes over a pulley free to ro

Lisa [10]

To solve this problem it is necessary to apply the concewptos related to Torque, kinetic movement and Newton's second Law.

By definition Newton's second law is described as

F= ma

Where,

m= mass

a = Acceleration

Part A) According to the information (and as can be seen in the attached graph) a sum of forces is carried out in mass B, it is obtained that,

$\sum F = m_b a$

$m_Bg-T_B = m_Ba$

$T_B = m_Bg-m_Ba$

In the case of mass A,

$\sum F = m_A a$

$T_A = m_Ag-m_Aa$

Making summation of Torques in the Pulley we have to

$\sum\tau = I\alpha$

$T_BR_0-T_AR_0=I\alpha$

$T_B-T_A=I\frac{a}{R^2_0}$

Replacing the values previously found,

$(m_Bg-m_Ba )-(m_Ag-m_Aa )=I\frac{a}{R^2_0}$

$(m_B-m_A)g-(m_B+m_A)a=I\frac{a}{R^2_0}$

$a = \frac{(m_B-m_A)g}{\frac{I}{R_0^2}+(m_B+m_A)}$

$a = \frac{(m_B-m_A)g}{\frac{MR^2_0^2/2}{R_0^2}+(m_B+m_A)}$

$a =\frac{(m_B-m_A)g}{\frac{M}{2}+(m_B+m_A)}$

Replacing with our values

$a =\frac{(8-6.8)(9.8)}{\frac{0.8}{2}+(8+6.8)}$

$a=0.7736m/s^2$

PART B) Ignoring the moment of inertia the acceleration would be given by

$a' =\frac{(m_B-m_A)g}{(m_B+m_A)}$

$a' =\frac{(8-6.8)(9.8)}{(8+6.8)}$

$a' = 0.7945$

Therefore the error would be,

$\%error = \frac{a'-a}{a}*100$

$\%error = \frac{0.7945-0.7736}{0.7736}*100$

$\%error = 2.7%$

8 0

2 years ago

If an incident light ray hits a flat smooth object at 28 degrees, it will reflect off at an angle of…

Nookie1986 [14]

Option B is correct. If an incident light ray hits a flat, smooth object at 28°. It will reflect off at an angle of 28°.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

If an incident light ray hits a flat, smooth object at 28 degrees, it will reflect off at an angle of 28°.

Hence, option B is correct

To learn more about the law of reflection, refer to the link;

brainly.com/question/12029226

#SPJ1

5 0

1 year ago

A boat traveling at a velocity of 20 m/s leaves island heading east . The boat slows to rest at a rate of 1.5 m/s2 How far away

ioda

The boat's initial velocity is:

$v_0 = 20 m/s$

While the boat's acceleration is

$a=-1.5 m/s^2$

with a negative sign, since the boat is slowing down, so it is a deceleration. The distance traveled by the boat until it comes to a stop can be found by using the following equation:

$v_f^2 -v_0^2 = 2aS$

where vf=0 is the final velocity of the boat and S is the distance covered. Re-arranging the formula, we can find S:

$S=\frac{-v_0^2}{2a}=\frac{-(20 m/s)^2}{2(-1.5 m/s^2)}=133.3 m$

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2 years ago