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zvonat [6]
3 years ago
12

Express in standard form (I)0.000038​

Physics
1 answer:
Tasya [4]3 years ago
7 0

Answer:

3.8 x 10^-5

Explanation:

all you doing is putting it in the standard form I hope this help

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A 2:2 kg toy train is con ned to roll along a straight, frictionless track parallel to the x-axis. The train starts at the origi
Liula [17]

Answer:

a) 10.51 J

b) 3.48 m/s

Explanation:

Given data :

mass of train ( M ) = 2.2 kg

Given initial velocity ( u ) = 1.6 m/s

<u>a) calculating work done by the force over the journey of the train</u>

F = mx + b  ------ ( 1 )

m = slope  = ( Δ f / Δ x ) = 2.8 / -7.5 = - 0.373 N/m

x = distance travelled on the x axis by the train = 7.5 m

F = force experienced by the train = 2.8 N

x = 0

∴ b = 2.8

hence equation 1 can be written as

F = ( -0.373) x + 2.8   ----- ( 2 )

hence to determine the work done by the force

W   = \int\limits^7_0 { ( -0.373) x + 2.8  )} \, dx     Note:  the limits are actually 7.5 and 0

∴ W ( work done ) = -10.49 + 21 = 10.51 J

<u>b) calculate the speed of the train at the end of its journey</u>

we will apply the work energy theorem

W = 1/2 m*v^2  -  1/2 m*u^2

∴ V^2 = 2 / M ( W + 1/2 M*u^2 )  ( input values into equation )

 V^2 = 12.11

hence V = 3.48 m/s

6 0
3 years ago
The total distance a group of movers move a refrigerator is 22 m. If they complete this task in 15 minutes, their efforts would
lianna [129]

Answer:

Their efforts would be expressed in units of Joules per second

Explanation:

The unit of their efforts can be derived from the formula of power which is given by the product of mass, acceleration and distance (the product is energy with unit joules) divided by time taken to complete the task (unit is seconds)

Therefore, the unit of their efforts would be joules per second

4 0
3 years ago
How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N
Arte-miy333 [17]

Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

           acceleration of object (a) = 22.35 m/s^{2}

                        Force exerted (F) = 120N

                        mass of an object (m) = ?

From Newton's second law of motion;

                                   F = ma

                           or, 120 = m × 22.35

                          or, m= \frac{120}{22.35} kg

                           ∴ m = 5.36 kg

3 0
2 years ago
A tuning fork labeled 392 Hz has the tip of each of its two prongsvibrating with an amplitude of 0.600mma) What is the maximum s
DanielleElmas [232]

a) 1.48 m/s

The tuning fork is moving by simple harmonic motion: so, the maximum speed of the tip of the prong is related to the frequency and the amplitude by

v_{max}=\omega A

where

v_{max} is the maximum speed

\omega is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

\omega=2\pi f=2 \pi(392 Hz)=2462 rad/s, where f is the frequency

A=0.600 mm=6\cdot 10^{-4} m is the amplitude

Therefore, the maximum speed is

v_{max}=(2462 rad/s)(6\cdot 10^{-4}m)=1.48 m/s

b)  3.0\cdot 10^{-5} J

The fly's maximum kinetic energy is given by

K=\frac{1}{2}mv_{max}^2

where

m=0.0270 g=2.7\cdot 10^{-5} kg is the mass of the fly

v_{max}=1.48 m/s is the maximum speed

Substituting into the equation, we find

K=\frac{1}{2}(2.7\cdot 10^{-5}kg)(1.48 m/s)^2=3.0\cdot 10^{-5} J

7 0
3 years ago
Sorin hits a cricket ball straight up into the air. After 1.5\,\text{s}1.5s1, point, 5, start text, s, end text, the ball is fal
Illusion [34]

Answer:

8.2 m/s upward

Explanation:

The motion of the ball is a free fall motion, so we can use the suvat equation:

v=u+at

where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

Choosing upward as positive direction:

v=-6.5 m/s

a=g=-9.8 m/s^2 (acceleration of gravity)

t = 1.5 s

Solving for u, we find the initial velocity:

u=v-at=-6.5-(-9.8)(1.5)=8.2 m/s

And the direction is upward.

3 0
3 years ago
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