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lord [1]
3 years ago
5

Le manque de sommeil peut réduire la production d'insuline par le pancréas. L'insuline est responsable de métaboliser le sucre d

ans le sang. De quel ordre peut être la réduction d'insuline?Lecteur immersif
Physics
1 answer:
Pavlova-9 [17]3 years ago
6 0

Answer:

Very big.

Explanation:

Very big reduction occurs in insulin production when a person did not sleep in 24 hours. Due to lack of sleep, reduction occurs in the production of insulin by the pancreas. Insulin is a hormone that is responsible for metabolizing sugar in the blood and if insulin is not secreted by the pancreas in normal concentration so the person get diabetes disease due to increasing amount of glucose in the blood.

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If you apply a 4 N force to a 2 kg object, how fast will it accelerate? (Your
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Answer:2n

Explanation:

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3 years ago
A truck, initially at rest, rolls down a frictionless hill and attains a speed of 20 m/s at the bottom. To achieve a speed of 40
Crank

Answer:

To achieve the velocity of 40 m/sec height will become 4 times  

Explanation:

We have given initially truck is at rest and attains a speed of 20 m/sec

Let the mass of the truck is m

At the top of the hill potential energy is mgh and kinetic energy is \frac{1}{2}mv^2

So total energy at the top of the hill =mgh+0=mgh

At the bottom of the hill kinetic energy is equal to \frac{1}{2}mv^2 and potential energy will be 0

So total energy at the bottom of the hill is equal to 0+\frac{1}{2}mv^2

Form energy conservation mgh=\frac{1}{2}mv^2

v=\sqrt{2gh}, for v = 20 m/sec

20=\sqrt{2\times 9.8\times h}

Squaring both side

19.6h=400

h = 20.408 m

Now if velocity is 0 m/sec

40=\sqrt{2gh}

19.6h=1600

h = 81.63 m

So we can see that to achieve the velocity of 40 m/sec height will become 4 times

5 0
3 years ago
What relationship does mass have with inertia
stira [4]
Inertia is a term that qualitatively describes the ability of a substance to resist changes in its state of motion, while mass gives a quantitative value for inertia
7 0
3 years ago
PLS HELP I HAVE EXAM ILL GIVE U BRAINLIST
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Explanation:

False

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3 0
3 years ago
How fast can a 4000 kg truck travel around a 70 m radius turn without skidding if its tires share a 0.6 friction coefficient wit
aleksley [76]

Answer:

Velocity of truck will be 20.287 m /sec

Explanation:

We have given mass of the truck m = 4000 kg

Radius of the turn r = 70 m

Coefficient of friction \mu =0.6

Centripetal force is given  F=\frac{mv^2}{r}

And frictional force is equal to F_{frictional}=\mu mg

For body to be move these two forces must be equal

So \frac{mv^2}{r}=\mu mg

v=\sqrt{\mu rg}=\sqrt{0.6\times 70\times 9.8}=20.287m/sec

7 0
3 years ago
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