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3 years ago

Which statement(s) accurately describe the conditions immediately before and after the firecracker explodes:

Physics

1 answer:

lidiya [134]3 years ago

8 0

Answer:

Option C, The total momentum of the fragments is equal to the original momentum of the firecracker.

Explanation:

Kinetic energy of cracker cannot remain constant before and after explosion. It is so because in the process of burning and bursting some amount of kinetic energy is lost in the form of light and heat energy. While the total mass before and after the explosion remains constant due to which the momentum is conserved before and after the explosion

Hence, option C is correct

You might be interested in

A 1.1-cm-diameter pipe widens to 2.34 cm, then narrows to 4.9 mm. Liquid flows through the first segment at a speed of 3.57 m/s.

ratelena [41]

Answer:

v2=0.79 m/s

Explanation:

equation of continuity: V1A1=V2A2

A=(pi)r^2

A1=(pi)(0.55cm)^2

A2=(pi)(1.17cm)^2

convert cm2->m2

A1= 0.95cm2=

A2= 4.3cm2=

(3.57 m/s)(0.000095 m^2)=(x m/s)(0.00043 m^2)

v2=0.79 m/s

hope this helped

6 0

3 years ago

Where tornadose occur in the usa

Leno4ka [110]

Tornadoes can occur all over the place, but are most commonly occuring in Tornado Alley (it's in the central of the US, In places like Oklahoma and stuff)

7 0

4 years ago

Read 2 more answers

A tractor pulls a 1,000 kg wagon with a force of 4,000N. What is the wagon’s acceleration in m/s2? *

Alla [95]

Answer:

4m/s^2

Explanation:

acceleration=force/mass

therefore a=4000/1000

=4m/s^2

8 0

3 years ago

g a long, straight wire carries a current an electron Is it necessary to include the effects of gravity?

stealth61 [152]

Answer:

The force is $3.2\times10^{-20}\ N$

Explanation:

Given that,

A long, straight wire carries a current.

Suppose, a long, straight wire carries a current 0.86 A. An electron is traveling in the vicinity of the wire. At the instant when the electron is 4.50 cm from the wire and traveling at speed of $6\times10^{4}\ m/s$ directly toward the wire. What are the magnitude of the force that the magnetic field of the current exerts on the electron?

We need to calculate the magnetic field

Using formula of magnetic field

$B=\dfrac{\mu_{0}I}{4\pi r}$

Where, I = current

r = distance

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times0.86}{2\pi\times4.5\times10^{-2}}$

$B=0.0000038\ T$

$B=3.8\times10^{-6}\ T$

We need to calculate the force

Using formula of force

$F=qvB\sin\theta$

Here, $\theta=90^{\circ}$

Where, q = charge of electron

v = velocity of electron

B = magnetic field

Put the value into the formula

$F=1.6\times10^{-19}\times6\times10^{4}\times3.8\times10^{-6}\sin90$

$F= 3.2\times10^{-20}\ N$

Hence, The force is $3.2\times10^{-20}\ N$

3 0

3 years ago

If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the objec

Solnce55 [7]

There are several information's of immense importance that are already given in the question. Based on those information's the answer to the question can be very easily determined.
Initial velocity of the object (V1) = 65 m/s
Final velocity of the object (V2) = 98 m/s
Time taken by the object = 12 seconds
Then
Acceleration of the object = (V2 - V1)/Time taken
      = (98 - 65)/12 m/s^2
   = 33/12 m/s^2
   = 2 9/12 m/s^2
   = 2.75 m/s^2
So the acceleration of the object can be written as 2 9/12 meter per square second or 2.75 meter per square second.

3 0

3 years ago