Simply simplify the ratios/fractions into their simplest fraction form and divide the numerator by the denominator. If they are equal, they are in fact proportions, if not, they aren't
slope intercept form
y=mx+b
where m is the slope and b is the y intercept
if we change from point slope form
y-y1 = m(x-x1)
we distribute
y-y1 = mx -x*x1
then add y1 to each side
y = mx -x*x1+y1
remember x and y are variables and should stay in the equation
m,x1,y1 are numbers from the problem
you may have to calculate the slope (m) from the formula
m = (y2-y1)/(x2-x1) from two points on the line
Answer:
We want a polynomial of smallest degree with rational coefficients with zeros in 
, 
and -3. The last root gives us the factor (x+3). Hence, our polynomial is
where 
is a polynomial with rational coefficients and roots and . The root gives us a factor 
, but in order to obtain rational coefficients we must consider the factor 
.
An analogue idea works with . For convenience write 
. This gives the factor 
. Hence,
Notice that 
. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is
Step-by-step explanation:
We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type 
will introduce in the expression, we need to multiply by its conjugate 
. Hence, we will obtain that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.
Answer:
1.37
Step-by-step explanation:
that is half of 2 and 3/4
