To fill the other element's shell.
Answer:
1.) AgNO₃
2.) 0.563 moles AgBr
Explanation:
The limiting reagent is the reagent that is used up completely during a reaction. It can be identified by calculating which reactant produces the smallest amount of product. This can be done by determining the number of moles of each reagent (via molarity conversion). and then converting it to moles of the product (via mole-to-mole ratio).
AgNO₃ (aq) + KBr (aq) ---> AgBr (s) + KNO₃ (aq)
Molarity (M) = moles / liters
100 mL = 1 L
AgNO₃
45.0 mL / 100 = 45.0 L
1.25 M = ? moles / 0.450 L
? moles = 0.563 moles
KBr
75.0 mL / 100 = 0.750 L
0.800 M = ? moles / 0.750 L
? moles = 0.600 moles
In this case, there is no need to use the mole-to-mole ratio because all of the coefficients are one in the reaction (the amount of the limiting reagent used is the same amount of product produced). Since AgNO₃ produces the smaller amount of product, it is the limiting reagent.
Answer:
603 mL
Explanation:
A milliliter is a unit of volume equal to 1/1000th of a liter. It is the same as a cubic centimeter.
Answer:
<u>CH</u>
Explanation:
Molecular formula of propene : <u>C₃H₆</u>
Take the HCF of carbon and hydrogen atoms :
Then, we can write the formula as :
- 3CH
- This means there are 3 moles present
Empirical Formula :
- Molecular Formula / No. of moles
- C₃H₆ / 3
- <u>CH</u>
<u></u>
The empirical formula of propene is <u>CH</u>
It makes it more accessible to everybody
