Answer:
The correct answer is "Secondary active transport".
Explanation:
Secondary active transport is a form of across the membrane transport that involves a transporter protein catalyzing the movement of an ion down its electrochemical gradient to allow the movement of another molecule or ion uphill to its concentration/electrochemical gradient. In this example, the transporter protein (antiporter), move 3 Na⁺ into the cell in exchange for one Ca⁺⁺ leaving the cell. The 3 Na⁺ are the ions moved down its electrochemical gradient and the one Ca⁺⁺ is the ion moved uphill its electrochemical gradient, because Na+ and Ca⁺⁺are more concentrated in the solution than inside the cell. Therefore, this scenario is an example of secondary active transport.
Answer : The correct option is, (C) 1.1
Solution : Given,
Initial moles of 
= 1.0 mole
Initial volume of solution = 1.0 L
First we have to calculate the concentration .
The given equilibrium reaction is,
Initially c 0
At equilibrium 
The expression of 
will be,
![K_c=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
where,
= degree of dissociation = 40 % = 0.4
Now put all the given values in the above expression, we get:
Therefore, the value of equilibrium constant for this reaction is, 1.1
Answer:
3,5-dimethyl-2-octene
Explanation:
Please note that there is no H at carbon 3 less carbon becomes penta hydra.
The compound is:
CH3
I
C = CH2 - CH3
I
CH2
I
CH - CH3
I
CH2
I
CH2
I
CH3
To name the above compound, do the following:
1. Locate the longest continuous chain i.e octene
2. Start counting from the side that gives the double bond the lowest low count since the double bond is the functional group. In doing this, the double bond is at carbon 2.
3. Locate the substituent groups attached and their position in the parent chain. In doing so, you will see that there are two CH3 group attached and they are at carbon 3 and carbon 5. Since the substituents attached are the same, we'll name them as 'dimethyl' indicate that they are two methyl groups
Now, we'll combine the above findings in order to obtain the name. Therefore, the name of the compound is:
3,5-dimethyl-2-octene
Answer:
0 percent chance.
Explanation:
If it is a male then the mom has to be a carrier or have the trait because the dad will pass on a Y, and the trait for colorblindness is linked to the X. If it is a female, she needs 2 of those traits (one from each parent), and since the mom cannot give one, there is not a chance of the kids having colorblindness.
