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maw [93]
3 years ago
15

What is the identity of the atom shown?

Chemistry
2 answers:
jonny [76]3 years ago
3 0
Niterogen if I’m wrong please correct me
umka21 [38]3 years ago
3 0

Answer:

Option A

Explanation:

The answer to this question is the first option or "fluorine." You can find the amount of protons, neutrons, and electrons by looking at the elements atomic number and mass number. In this case we have the first option fluorine which it's atomic number is nine which is why the element has nine protons, and electrons, and nine neutrons because of it's mass number.

Hope this helps.

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I think it is D but i'm not sure

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The empirical formula of a compound of iron (Mg) and sulfur (S) was determined using the following data. A sample of Mg was weig
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Answer:

The empirical formula is MgS

The number of moles Mg is 0.25 moles

There will react 0.25 moles

Option A is correct

Explanation:

Step 1: data given

The molecular weight of Mg = 24.305 g/mol

The molecular weight of S is 32.065 g/mol

mass of crucible and cover = 27.631 grams

mass of crucible, cover and Mg = 33.709 grams

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Mass of Mg = mass of crucible, cover and Mg - mass of crucible and cover

Mass of Mg = 33.709 grams - 27.631 grams

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Step 3: Calculate moles Mg

Moles Mg = mass Mg / atomic mass Mg

Moles Mg = 6.078 grams 24.305 g/mol

Moles Mg = 0.250 moles

Step 4: Calculate mass compound

Mass compound = mass of crucible, cover, and the compound formed - mass of crucible and cover

Mass compound = 41.725 grams - 27.631 grams

Mass compound = 14.094 grams

Step 5: Calculate mass sulfur

Mass sulfur = 14.094 grams - 6.078 grams

Mass sulfur = 8.016 grams

Step 6: Calculate moles Sulfur

Moles sulfur = 8.016 grams / 32.065 g/mol

Moles sulfur = 0.250 moles

Step 7: Calculate the mol ratio

We diviide by the smallest amount of moles

Mg: 0.250 moles / 0.250 moles = 1

S: 0.250 moles / 0.250 moles = 1

The empirical formula is MgS

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There will react 0.25 moles

Option A is correct

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